anonymous
  • anonymous
~*~*~help please!! 10 points n medal!!~*~*~ Find the measure of angle A (image below). Round the answer to the nearest tenth. A. 49.5° B. 53.1° C. 63.4° D. 66.4°
Mathematics
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anonymous
  • anonymous
~*~*~help please!! 10 points n medal!!~*~*~ Find the measure of angle A (image below). Round the answer to the nearest tenth. A. 49.5° B. 53.1° C. 63.4° D. 66.4°
Mathematics
schrodinger
  • schrodinger
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misty1212
  • misty1212
hi!!
misty1212
  • misty1212
is it a law of sines question? or law of cosines?
anonymous
  • anonymous
cosines! my computer is whack and notloading up anything

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misty1212
  • misty1212
you got all 3 sides labelled?
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
there we go! thank you!
misty1212
  • misty1212
\[4^2=2^2+5^2-2\times 5\times \cos(A)\]
misty1212
  • misty1212
so \[16=29-10\cos(A)\]
misty1212
  • misty1212
first we get \(\cos(A)\) by itself, then A
misty1212
  • misty1212
\[\cos(A)=\frac{13}{10}=1.3\]hmm made a mistake somewhere
anonymous
  • anonymous
hey sorry, i dont have a calculator, give me a minuet to look
misty1212
  • misty1212
oh doh
misty1212
  • misty1212
\[2\times2\times 5=20\]
anonymous
  • anonymous
no batteries ):
misty1212
  • misty1212
\[4^2=2^2+5^2-2\times 5\times2\times \cos(A)\]\[16=29-20\cos(A)\] so \[\cos(A)=\frac{13}{20}=.65\]
misty1212
  • misty1212
lol use wolfram
misty1212
  • misty1212
\[A=\cos^{-1}(.65)\]
misty1212
  • misty1212
here http://www.wolframalpha.com/input/?i=arccos%28.65%29
anonymous
  • anonymous
0.863212!
misty1212
  • misty1212
look at the degree answer since your answers are in degrees
misty1212
  • misty1212
you see it?
anonymous
  • anonymous
i am unsure of how to get the degree! im sorry
misty1212
  • misty1212
look at the link i sent it is right there
anonymous
  • anonymous
49.46! thank you
misty1212
  • misty1212
i typed in \(\arccos(.65)\) in to wolfram, it gives the answer in radians and also in degrees
misty1212
  • misty1212
\[\color\magenta\heartsuit\]

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