anonymous
  • anonymous
The graph of a function f(x) is shown below: graph of line segment with endpoints at negative two, negative one and three, three. The negative two, negative one endpoint is open and the three, three endpoint is closed. What is the domain of f(x)? −2 < x ≤ 3 −2 ≤ x < 3 −1 < y ≤ 3 −1 ≤ y < 3
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Someone please help me @kearston0?
anonymous
  • anonymous
anonymous
  • anonymous

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anonymous
  • anonymous
Can you put up a picture of the graph? I think it would make it easier for me to understand ^.^
anonymous
  • anonymous
sure no problem
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Ok Ima take a shot at it...
anonymous
  • anonymous
Domain is X so on the graph there's a point (-2, -1) So x would be -2
anonymous
  • anonymous
|dw:1437000760769:dw|
anonymous
  • anonymous
So of the choices, A or B could be the answer?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
@eninone i still don't understand
anonymous
  • anonymous
|dw:1437001095578:dw|
anonymous
  • anonymous
Since we narrowed it down we can look at the dots on the graph, -2,-1 point is "Open" while 3, 3 is "closed".
anonymous
  • anonymous
@eninone can you explain better?
anonymous
  • anonymous
|dw:1437001167488:dw|
anonymous
  • anonymous
I think it should be A if you make a Quandaries and Queries chart...
jdoe0001
  • jdoe0001
@Noelia when asked for "domain", what is that?
anonymous
  • anonymous
Their is only supposed to be one answer @eninone
anonymous
  • anonymous
@jdoe0001 it means find the x value (domain is x)
anonymous
  • anonymous
Too clarify < or > is open and Less than greater than equal too is closed...
jdoe0001
  • jdoe0001
|dw:1437002172953:dw|
jdoe0001
  • jdoe0001
notice the -2 has a "hole" in it, thus is EXCLUDED from the domain, so "x" is never -2
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1437001495141:dw|
anonymous
  • anonymous
−2 < x ≤ 3
anonymous
  • anonymous
so it is -2
anonymous
  • anonymous
−2 < x ≤ 3
jdoe0001
  • jdoe0001
so.. .whatever "x" is, or the domain we know that is NOT -2, but we know that, as it moves away from -2 and to 0, "x" is that and keeps on going till it gets to 3 bear in mind that, on the negative quadrants, the nuimbers closer to 0, are "bigger" thus -3 is really smaller than -2, because -2 is closer to 0 and -1 is bigger than -2 because -1 is closer to 0 so "x" is NOT -2, but bigger than that, and keeps on going till it gets to +3
anonymous
  • anonymous
domain= x is less than or equal to 3 and greater than -2.
anonymous
  • anonymous
So A?
anonymous
  • anonymous
@Noelia yep!
anonymous
  • anonymous
Ok thanks. Can you help me with another problem?
anonymous
  • anonymous
why not, post!
anonymous
  • anonymous
ok hold on

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