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anonymous

  • one year ago

Brian has started a savings account. The balance, g(x), in his account can be represented by the function g(x) = 25x + 350, where x is the number of weeks he deposits money. Suppose 25 changed to 35. What does this mean in the context of the problem

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  1. anonymous
    • one year ago
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    25x is variable amount

  2. anonymous
    • one year ago
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    answer choices changing 25 to 35 means his initial deposit increased changing 25 to 35 means his initial deposit decreased changing 25 to 35 means the amount he deposits each week increased changing 25 to 35 means the amount he deposits each week decreased

  3. anonymous
    • one year ago
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    C

  4. jdoe0001
    • one year ago
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    \(\large \begin{array}{llll} g(x) = &{\color{brown}{ 25 }} x + &350\\ &{\color{brown}{ slope}}&y-intercept \end{array}\qquad slope=\textit{rate of change}\)

  5. jdoe0001
    • one year ago
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    he deposits in his acccount every "x" amount of weeks originally it'd be every 25x weeks if 25 changes to 35, then it'd be 35x so he'd be depositing every 35x weeks

  6. jdoe0001
    • one year ago
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    the hmm wording is a bit misleading 25x means... every "x" week he deposits 25 bucks so say on week 1, x =1 and his deposit is 25(1) week 2, x = 2 and his deposit is 25(2) and so on so if 25 changes to 35 then on week 1, he'd be depositing 35(1) and on week 2, 35(2) and so on

  7. anonymous
    • one year ago
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    Write the equation of a line with a slope of –1 and a y-intercept of –6

  8. anonymous
    • one year ago
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    is it y =-x-6

  9. jdoe0001
    • one year ago
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    \(\bf \begin{array}{llll} f(x) = &{\color{brown}{ -1 }} x + &-6\\ &{\color{brown}{ slope}}&y-intercept \end{array}\) graph it away

  10. jdoe0001
    • one year ago
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    yeap

  11. anonymous
    • one year ago
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    Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form

  12. anonymous
    • one year ago
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    i think it is y=-5x-10

  13. jdoe0001
    • one year ago
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    \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ -3}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 10}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form} \)

  14. jdoe0001
    • one year ago
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    same as the one before... you may want to post anew, more eyes btw

  15. anonymous
    • one year ago
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    slope is -5

  16. anonymous
    • one year ago
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    y-int is -10

  17. anonymous
    • one year ago
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    i did that and i got y=5x+8

  18. jdoe0001
    • one year ago
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    hmmm got a typo darn it \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ -3}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 10}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 10}}-{\color{blue}{ 5}}}{{\color{red}{ 2}}-{\color{red}{ (-3)}}}\implies \cfrac{5}{2+3}\implies \cfrac{\cancel{5}}{\cancel{5}}\implies 1 \\ \quad \\ % point-slope intercept y-{\color{blue}{ 5}}={\color{green}{ 1}}(x-{\color{red}{ (-3)}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)

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