anonymous
  • anonymous
The table below shows the data for a random sample of fish that were collected from and later released into a lake: How many catfish are estimated to be present if a sample of 800 fish is collected from the lake? 208 260 348 372
Mathematics
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anonymous
  • anonymous
The table below shows the data for a random sample of fish that were collected from and later released into a lake: How many catfish are estimated to be present if a sample of 800 fish is collected from the lake? 208 260 348 372
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
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kropot72
  • kropot72
Add the numbers of Catfish, Grass carp and Bluegill that were in the sample. Call that total number n. Then the probability of a Catfish in a very large sample of fish is 52/n. Therefore to estimate the number of Catfish in a sample of 800 we need to calculate \[\large \frac{52}{n} \times \frac{800}{1}=you\ can\ calculate.\]
anonymous
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anonymous
  • anonymous
@kropot72 i dont understand
kropot72
  • kropot72
The total number of fish in the first sample is 52 + 61 + 87 = 200 Therefore to estimate the number of Catfish in a sample of 800 we need to calculate \[\large \frac{52}{200} \times \frac{800}{1}=?\]
anonymous
  • anonymous
kropot72
  • kropot72
Yes, 208 Catfish is correct.

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