UnbelievableDreams
  • UnbelievableDreams
Confusing math question
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
UnbelievableDreams
  • UnbelievableDreams
csc(3∝+40)=sec(7∝−70)
zzr0ck3r
  • zzr0ck3r
Do they mean the limit?
jdoe0001
  • jdoe0001
so... what's the question at -> \(\bf csc(3\alpha+40)=sec(7\alpha-70)?\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

UnbelievableDreams
  • UnbelievableDreams
Find the ∝
UnbelievableDreams
  • UnbelievableDreams
@jdoe0001
sdfgsdfgs
  • sdfgsdfgs
3 eqns that can be used to solve the prob. \[\csc A = \frac{ 1 }{ \sin A }\] \[\sec A = \frac{ 1 }{ \cos A }\] and \[\sin (\frac{ \pi }{ 2 } - A) = \cos A\]
anonymous
  • anonymous
wow
anonymous
  • anonymous
are you supposed to find one answer, or all of them? one will be no problem, all will be almost impossible
UnbelievableDreams
  • UnbelievableDreams
Just one answer, I am confused about tis formula
anonymous
  • anonymous
one answer we can start with \[\frac{1}{\cos(3x+40)}=\frac{1}{\sin(7x-70)}\]
anonymous
  • anonymous
or \[\cos(3x+40)=\sin(7x-70)\]
anonymous
  • anonymous
damn i have that backwards!!
anonymous
  • anonymous
\[\sin(3x+40)=\cos(7x-70)\]
UnbelievableDreams
  • UnbelievableDreams
x=12, right?
anonymous
  • anonymous
idk i am still working
anonymous
  • anonymous
add \(90\) to \(7x-70\) to get \[\cos(7x-70)=\sin(7x+20)\]
anonymous
  • anonymous
so one answer will be the solution to \[3x+40=7x+20\]
anonymous
  • anonymous
i get \(x=5\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.