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UnbelievableDreams
 one year ago
Confusing math question
UnbelievableDreams
 one year ago
Confusing math question

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UnbelievableDreams
 one year ago
Best ResponseYou've already chosen the best response.0csc(3∝+40)=sec(7∝−70)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Do they mean the limit?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0so... what's the question at > \(\bf csc(3\alpha+40)=sec(7\alpha70)?\)

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.03 eqns that can be used to solve the prob. \[\csc A = \frac{ 1 }{ \sin A }\] \[\sec A = \frac{ 1 }{ \cos A }\] and \[\sin (\frac{ \pi }{ 2 }  A) = \cos A\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you supposed to find one answer, or all of them? one will be no problem, all will be almost impossible

UnbelievableDreams
 one year ago
Best ResponseYou've already chosen the best response.0Just one answer, I am confused about tis formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one answer we can start with \[\frac{1}{\cos(3x+40)}=\frac{1}{\sin(7x70)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or \[\cos(3x+40)=\sin(7x70)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn i have that backwards!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin(3x+40)=\cos(7x70)\]

UnbelievableDreams
 one year ago
Best ResponseYou've already chosen the best response.0x=12, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk i am still working

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0add \(90\) to \(7x70\) to get \[\cos(7x70)=\sin(7x+20)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so one answer will be the solution to \[3x+40=7x+20\]
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