## UnbelievableDreams one year ago Confusing math question

1. UnbelievableDreams

csc(3∝+40)=sec(7∝−70)

2. zzr0ck3r

Do they mean the limit?

3. jdoe0001

so... what's the question at -> $$\bf csc(3\alpha+40)=sec(7\alpha-70)?$$

4. UnbelievableDreams

Find the ∝

5. UnbelievableDreams

@jdoe0001

6. sdfgsdfgs

3 eqns that can be used to solve the prob. $\csc A = \frac{ 1 }{ \sin A }$ $\sec A = \frac{ 1 }{ \cos A }$ and $\sin (\frac{ \pi }{ 2 } - A) = \cos A$

7. anonymous

wow

8. anonymous

are you supposed to find one answer, or all of them? one will be no problem, all will be almost impossible

9. UnbelievableDreams

10. anonymous

one answer we can start with $\frac{1}{\cos(3x+40)}=\frac{1}{\sin(7x-70)}$

11. anonymous

or $\cos(3x+40)=\sin(7x-70)$

12. anonymous

damn i have that backwards!!

13. anonymous

$\sin(3x+40)=\cos(7x-70)$

14. UnbelievableDreams

x=12, right?

15. anonymous

idk i am still working

16. anonymous

add $$90$$ to $$7x-70$$ to get $\cos(7x-70)=\sin(7x+20)$

17. anonymous

so one answer will be the solution to $3x+40=7x+20$

18. anonymous

i get $$x=5$$

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