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FelicityFicca
 one year ago
In which line did the student make the first mistake?
A student solved the following problem and made an error:
Triangles ABC and DEF.
Angles A and F are congruent and measure 63 degrees.
Coordinates for the vertices are at
A (1, 2) and B (1, 4) and C (3, 3)
D (5, 1) and E (3, 2) and F (5, 3)
(IMAGE 1)
Line 1 segment AB equals 2, segment FD equals 2,
segment AB is congruent to segment FD
(IMAGE 2)
Line 2 ∠A ≅ ∠F
Line 3 Length of segment AC.
A (1, 2)
C (3, 3)
(IMAGE 3)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5
segment AC = 2.23
Line 4 Length of segment EF.
E (3, 2)
F (5, 3)
(IMAGE 4)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5
segment EF= 2.23
Line 5 segment AC is congruent to segment FE
Line 6 triangle ABC is congruent to triangle EFD by SAS
FelicityFicca
 one year ago
In which line did the student make the first mistake? A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 63 degrees. Coordinates for the vertices are at A (1, 2) and B (1, 4) and C (3, 3) D (5, 1) and E (3, 2) and F (5, 3) (IMAGE 1) Line 1 segment AB equals 2, segment FD equals 2, segment AB is congruent to segment FD (IMAGE 2) Line 2 ∠A ≅ ∠F Line 3 Length of segment AC. A (1, 2) C (3, 3) (IMAGE 3) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5 segment AC = 2.23 Line 4 Length of segment EF. E (3, 2) F (5, 3) (IMAGE 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5 segment EF= 2.23 Line 5 segment AC is congruent to segment FE Line 6 triangle ABC is congruent to triangle EFD by SAS

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