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You were given a triangle like this:
|dw:1437006808180:dw|

What do the circled marks mean?
|dw:1437006848302:dw|

doesn't it mean its equal

\(\Large P_{triangle} = a + b + c\)
where a, b, and c are the lengths of the sides of the triangle.

\(P = 2a + 2a + 2a = 6a\)
The perimeter of the triangle is 6a mm

Ok so far?

Yes. It's the same as what i got @mathstudent55

Now you have to find the area.

And I would do that how ? Because I don't have the heigh . I have the base is 2

Have you heard about the ratios of the lengths of the sides of a 30-60-90 triangle?

Yes but I never understood it

The length of the long leg is \(\sqrt 3\) times the length of the short leg.

|dw:1437011291789:dw|

Do you understand so far?

sort of

how do I get the height out of this?

Ok. Let's get back to our problem.

|dw:1437011694076:dw|

|dw:1437011786387:dw|

|dw:1437011853170:dw|

Look at the small triangle in the circle and ignore the rest.
|dw:1437012005959:dw|

|dw:1437012157126:dw|

|dw:1437012211126:dw|

so is the height 3a?

Now we have all the info we need to find the area of the large triangle.

The height is \(\sqrt 3 a\), not 3a.
\(\Large A_{triangle} = \dfrac{bh}{2} \)

\(\Large A = \dfrac{(a)(\sqrt 3 a)}{2} = \dfrac{\sqrt 3}{2}a^2 ~mm^2\)

thanks!!!

You're welcome.