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Summersnow8
 one year ago
(1) A bullet with mass 50.0 g is fired with an initial velocity of 625 m/s from a gun with a mass 3.50 kg. What is the speed of recoil (in m/s) of the gun?
(2) How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s?
Summersnow8
 one year ago
(1) A bullet with mass 50.0 g is fired with an initial velocity of 625 m/s from a gun with a mass 3.50 kg. What is the speed of recoil (in m/s) of the gun? (2) How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s?

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shamim
 one year ago
Best ResponseYou've already chosen the best response.01) Use conservation of momentum law

shamim
 one year ago
Best ResponseYou've already chosen the best response.0m1*u1+m2*u2=m1*v1+m2*v2

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0what does u stand for?

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0could you work me through it? i'm not too familiar with that formula

shamim
 one year ago
Best ResponseYou've already chosen the best response.0m1=mass off bullet=50g=?kg m2=mass of gun=3.5kg u1=initial velocity of bullet=0 u2=initial velocity of gun=0 v1=final velocity of bullet =625m/s v2=?

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0(0.05 kg)(625 m/s)+(3.5 kg)(0 m/s)= (0.065 kg)(625 m/s)+ (3.5 kg)v2

shamim
 one year ago
Best ResponseYou've already chosen the best response.0m1=50g=50/1000kg=.05kg Right?

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1i think it should be (0.05 kg)(0 m/s)+(3.5 kg)(0 m/s)= (0.06 kg)(625 m/s)+ (3.5 kg)v2

shamim
 one year ago
Best ResponseYou've already chosen the best response.0.05*0+3.5*0=.05*625+.05*v2 v2=?

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0i got 31.25 = 31.25 + 3.5 V2

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1no you may be using the wrong equation the correct one is 05*0+3.5*0=.05*625+.05*v2 as @shamim said

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1so you should get 31.25=3.5v2 and i posted the wrong equation it should be 05*625+3.5*v2

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0V2 = 8.9285 m/s, but since speed is scalar it is just 8.9285

shamim
 one year ago
Best ResponseYou've already chosen the best response.0Left hand side of my equation will b 0 Right?

shamim
 one year ago
Best ResponseYou've already chosen the best response.0 reveals v1 nd v2 r oposit in direction

shamim
 one year ago
Best ResponseYou've already chosen the best response.0Ur bullet is going to forward nd ur gun is going to backward

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0how do I solve #2 now?

shamim
 one year ago
Best ResponseYou've already chosen the best response.0Who will get medal?????!!!!!

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0whoever helps me solve both problems

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s?

shamim
 one year ago
Best ResponseYou've already chosen the best response.0U should post ur second question again in another post

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1thanks for the medal @Summersnow8

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0@rajat97 no problem
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