Summersnow8
  • Summersnow8
(1) A bullet with mass 50.0 g is fired with an initial velocity of 625 m/s from a gun with a mass 3.50 kg. What is the speed of recoil (in m/s) of the gun? (2) How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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shamim
  • shamim
1) Use conservation of momentum law
shamim
  • shamim
m1*u1+m2*u2=m1*v1+m2*v2
Summersnow8
  • Summersnow8
what does u stand for?

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Summersnow8
  • Summersnow8
could you work me through it? i'm not too familiar with that formula
shamim
  • shamim
m1=mass off bullet=50g=?kg m2=mass of gun=3.5kg u1=initial velocity of bullet=0 u2=initial velocity of gun=0 v1=final velocity of bullet =625m/s v2=?
shamim
  • shamim
v2=recoil speed of gun
shamim
  • shamim
No
Summersnow8
  • Summersnow8
(0.05 kg)(625 m/s)+(3.5 kg)(0 m/s)= (0.065 kg)(625 m/s)+ (3.5 kg)v2
shamim
  • shamim
m1=50g=50/1000kg=.05kg Right?
rajat97
  • rajat97
i think it should be (0.05 kg)(0 m/s)+(3.5 kg)(0 m/s)= (0.06 kg)(625 m/s)+ (3.5 kg)v2
shamim
  • shamim
.05*0+3.5*0=.05*625+.05*v2 v2=?
shamim
  • shamim
Why .06 kg?
rajat97
  • rajat97
oh! i'm sorry
rajat97
  • rajat97
*0.05kg
Summersnow8
  • Summersnow8
i got 31.25 = 31.25 + 3.5 V2
rajat97
  • rajat97
no you may be using the wrong equation the correct one is 05*0+3.5*0=.05*625+.05*v2 as @shamim said
shamim
  • shamim
.05*0=0 Right?
rajat97
  • rajat97
so you should get -31.25=3.5v2 and i posted the wrong equation it should be 05*625+3.5*v2
shamim
  • shamim
3.5*9=0 Right?
shamim
  • shamim
0+0=0 Right?
Summersnow8
  • Summersnow8
V2 = -8.9285 m/s, but since speed is scalar it is just 8.9285
shamim
  • shamim
Left hand side of my equation will b 0 Right?
shamim
  • shamim
- reveals v1 nd v2 r oposit in direction
shamim
  • shamim
Ur bullet is going to forward nd ur gun is going to backward
Summersnow8
  • Summersnow8
how do I solve #2 now?
shamim
  • shamim
Who will get medal?????!!!!!
Summersnow8
  • Summersnow8
whoever helps me solve both problems
Summersnow8
  • Summersnow8
How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s?
shamim
  • shamim
U should post ur second question again in another post
Summersnow8
  • Summersnow8
ok
rajat97
  • rajat97
thanks for the medal @Summersnow8
Summersnow8
  • Summersnow8
@rajat97 no problem

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