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anonymous

  • one year ago

Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the function f). k = 2; f(x) = 2x3 + 4x2 + 2x - 4; Lower bound? I believe that it is lower bound, is that correct? How would I solve this?

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  1. Mertsj
    • one year ago
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    Possible zeros: \[\pm\frac{4}{1},\pm\frac{4}{2},\pm\frac{2}{1},\pm\frac{2}{2}, \pm\frac{1}{1},\pm\frac{1}{2}\] or: \[\pm4, \pm2, \pm1, \pm\frac{1}{2}\]

  2. Mertsj
    • one year ago
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    \[f(x)=2(x^2+2x^2+x-2)=0\] \[x^3+2x^2+x-2=0\]

  3. Mertsj
    • one year ago
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    |dw:1437012555983:dw|

  4. Mertsj
    • one year ago
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    |dw:1437012814980:dw|

  5. Mertsj
    • one year ago
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    So we see there is a zero between 2 and 1/2 and since f(2) is positive and f(1/2) is negative, 2 is an upper bound.

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