Summersnow8
  • Summersnow8
How many Newtons of force are required to stop a truck 2250 kg truck going 32.0 km/h in 4.00s? @rajat97
Physics
chestercat
  • chestercat
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shamim
  • shamim
I m not solving ur problem. Because u did not give me medal in ur previous problem
rajat97
  • rajat97
here, we just need to find the acceleration of the truck(i mean deceleration) and then multiply it with the mass of the truck first we convert everything into SI units the initial speed=u=32km/hr=8.89 m/s the final speed=v=0m/s time=t=4s we can use the kinematical equation v=u+at where a is the acceleration and all the other variables are defined above so from here, you get the acceleration (or the deceleration as we want to stop the truck) of the truck and then we just need to multiply the value of a i.e. acceleration with the mass of the truck i.e. 2250Kg
rajat97
  • rajat97
i may not be very clear so just feel free to ask anything

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Summersnow8
  • Summersnow8
how do you find Newtons from all this information?
rajat97
  • rajat97
by Newtons in the question, they mean 'Force' and we know, force is F=mass x ?
Summersnow8
  • Summersnow8
\[a = \frac{ V-u }{ t } = \frac{ 0-8,888 }{ 4.00 } = -2.22\] \[F = m * a = (2250 * -2.222) = -5000\]
Summersnow8
  • Summersnow8
*8.888
rajat97
  • rajat97
Awesome! you are absolutely right!
Summersnow8
  • Summersnow8
do i keep the - sign?
rajat97
  • rajat97
the -ve sign just means that the force is applied in opposite direction to that of the motion of the object which is the truck here
Summersnow8
  • Summersnow8
so if i submit an answer, should I submit 5000 or -50000
rajat97
  • rajat97
you should submit just 5000 as they have asked 'how many newtons' and not the direction of the force i.e. only magnitude
Summersnow8
  • Summersnow8
okay thanks for your help
rajat97
  • rajat97
any time girl!

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