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anonymous

  • one year ago

two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb directed up to the right at 30degrees with the horizontal and force Q is 100 lb directed up to the left at 60degrees with the horizontal, determine the moment of the resultant of these two forces with respect to O.

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  1. rajat97
    • one year ago
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    we have to use \[\tau=F \times r \] first of all we need to break the forces into their components-horizontal and vertical here we use the formula \[\tau=F _{perpendicular}\times r\] or \[\tau=F \times r_{perpendicular}\] both are the same the formula says that we need to multiply the magnitudes of the force and the radius vector which are perpendicular this is the original condition: |dw:1437014598098:dw| and when we break the forces into horizontal and vertical components, this becomes the situation: |dw:1437014784189:dw| we choose the reference point to be the moment center O now we multiply the force components with their perpendicular distances from the moment center. then we determine the direction of the moments due to each component and then add or subtract the moments accordingly and that is the final answer! I may not be very clear so please feel free to ask anything about this

  2. anonymous
    • one year ago
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    how can i determine the sign?im confuse of that...thanks for ur answer by the way..!

  3. rajat97
    • one year ago
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    thanks for the medal! we can determine the sign by using the cross product rule we know, torque is the cross product of radius and the force (the sequence of radius and force is important) you put your fingers in the direction of the radius vector and then curl them towards the force vector and then outstretch your thumb. Then your thumb shows the direction of the moment.

  4. rajat97
    • one year ago
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    well where are you from?

  5. anonymous
    • one year ago
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    from philippines..is that the right hand rule u mean?

  6. anonymous
    • one year ago
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    my answer is -379.79 lb-ft

  7. rajat97
    • one year ago
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    yes that's the right hand rule and by the way i am from india

  8. rajat97
    • one year ago
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    i'm working on the answer

  9. rajat97
    • one year ago
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    i got the answer=76.795

  10. anonymous
    • one year ago
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    here my drawing and answer

  11. rajat97
    • one year ago
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    okay! i made the wrong drawing

  12. rajat97
    • one year ago
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    it should be P(y)(4) + Q(y)(4) + Q(x)(3) - P(x)(3)

  13. anonymous
    • one year ago
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    why negative px?is that because of direction of x is negative in P?

  14. anonymous
    • one year ago
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    is that mean the answer is positive 379.79lb-ft

  15. rajat97
    • one year ago
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    i assumed the direction into the plane to be negative and direction and the direction out of the plane to be positive the right hand thumb rule

  16. anonymous
    • one year ago
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    so whats ur answer?

  17. rajat97
    • one year ago
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    my answer is 376.7949 very close to yours

  18. anonymous
    • one year ago
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    same answer

  19. rajat97
    • one year ago
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    okay then maybe it's correct

  20. rajat97
    • one year ago
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    okay i got it you took into account the direction of the forces and i just manipulated it without taking in account the negative sign of the Qx component

  21. anonymous
    • one year ago
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    what do u mean?

  22. rajat97
    • one year ago
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    the Qx component is directing towards left so it's sign is negative according to the sign convention

  23. anonymous
    • one year ago
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    yes thats what i understand...thats what im asking u..is that correct?is there a general rule for the sign?some says its positive if clockwise and negative when counterclockwise?some says because of direction and u said use a right hand rule...

  24. rajat97
    • one year ago
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    look just forget it! use the right hand rule properly and you'll get the correct answer choose one direction to be positive and the other to be negative generally if not specified in the question, we assume the outward direction to be positive and vice-versa. i'll be back in 15 mins. i have to bath

  25. rajat97
    • one year ago
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    thanks for the medal @SurpriseBreeze

  26. rajat97
    • one year ago
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    :)

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