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frank0520

  • one year ago

Suppose f(x,y) is harmonic (f has continuous second partials and fxx +fyy =0) and define the vector field Perp(f)=<-fy,fx> a) Show that Perp(f) is a conservative vector field that is orthogonal to Grad(f). Hint: To show that Perp(f) is conservative use one of the equivalent properties. b) Since Perp(f) is conservative it has a potential function g(x,y) called the harmonic conjugate of f(x,y). Show that g(x,y) is in fact harmonic.

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  1. frank0520
    • one year ago
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  2. ganeshie8
    • one year ago
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    For part a, use the given hint : If the vector field is conservative, then the curl is 0

  3. ganeshie8
    • one year ago
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    \[\text{Perp(f)} = \langle -f_y,~f_x\rangle\] find the curl

  4. anonymous
    • one year ago
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    if \(\nabla g=\langle -f_y,f_x\rangle\) then it follows \(g_x=-f_y,g_y=f_x\) so it follows $$g_{xx}=\frac{\partial}{\partial x}(-f_y)=-f_{xy}\\g_{yy}=\frac{\partial}{\partial y}(f_x)=f_{yx}$$so it follows by symmetry of mixed partials \(f_{xy}=f_{yx}\) that \(g_{xx}+g_{yy}=-f_{xy}+f_{yx}=0\), i.e. \(g\) is indeed harmonic

  5. anonymous
    • one year ago
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    to prove \(\langle -f_y,f_x\rangle=\langle -f_y,f_x,0\rangle\) as a vector field on \(\mathbb{R}^3\) is conservative, we can show \(\nabla\times f=\langle0,0,\frac{\partial}{\partial x}(f_x)-\frac{\partial}{\partial y}(-f_y)\rangle=\langle0,0,f_{xx}+f_{yy}\rangle=0\) since we're told \(f\) is harmonic (i.e. \(f_{xx}+f_{yy}=0\))

  6. anonymous
    • one year ago
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    to show it's orthogonal to \(\nabla f=\langle f_x,f_y\rangle\) you can compute their dot product: $$\langle -f_y,f_x\rangle\cdot\langle f_x,f_y\rangle=-f_yf_x+f_xf_y=0$$

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