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## DominiRican1013 one year ago The expression (secx + tanx)2 is the same as _____.

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1. anonymous

$(\sec x + \tan x)^2$ Remember how to expand out a squared expression like this? :)

2. DominiRican1013

$(\frac{ 1 }{ cosx }+\frac{ sinx }{ cosx})^2 ?$

3. anonymous

Before we continue, is there by chance choices?

4. DominiRican1013

yes hold on...

5. anonymous

If you're able to get past that first part, here is a hint to help you finish it up. Remember your Pythagorean identity for tangent, $\sec ^2x=1+\tan ^2x$

6. DominiRican1013

$A. 1+2\tan^2+2secx tanx$ $B. 1+2cscx$ $C. \sec^2x+\tan^2x$ $D. \sec^2x+2cscx+\tan^2x$

7. DominiRican1013

These are the choices

8. anonymous

Well after you expand you would get $\sec^2(x)+2\sec(x)\tan(x)+\tan^2(x)$

9. anonymous

But remember after you expand everything out, you can replace the sec^2x(that you'll end up with) with 1+tan^2x.

10. DominiRican1013

I'm so lost What I have so far is 1+tan(x)+2sec(x)tan(x)+1

11. anonymous

Expand the original equation like you would a binomial

12. anonymous

except in this case instead of (a+b)^2 A is Sec (x) and B is Tan (x)

13. anonymous

look at my previous posts, they are the exact steps on how to do this.

14. DominiRican1013

so it's A

15. anonymous

yes

16. DominiRican1013

thank you

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