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anonymous

  • one year ago

"For the given statement Pn, write the statements P1, Pk, and Pk+1." 2 + 4 + 6 + . . . + 2n = n(n+1) Could someone show me how to do this problem?

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  1. anonymous
    • one year ago
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    @ganeshie8 will you be able to help me?

  2. anonymous
    • one year ago
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    P1-->n=1 .2=1*2 Pk-->n=k 2+4+6+...+2k=k(k+1) pK+1--> n=k+1 2+4+6+8+...+2k+2(k+1)=(k+1)(k+2) then we should show that, if the proposition is true for an arbitrary number k, then it must be true for the next number:k+1 2+4+6+...+2k+(2k+2)=k^2+k+2k+2=k^2+3k+2=(k+1)(k+2) so we proved that if we add 2(k+1) to HYPOTHESIS we can prove that 2+4+6+8+...+2k+2(k+1)=(k+1)(k+2)

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