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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How can you solve this algebraically ln(x2x) =ln 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well both arguments should be the same, just equal both and solve the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2x = 6 i know the answer is 3 but don't know how to express it algebraically

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Hint: \[\huge e^{lnx} = x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well I'm using the one to one property of exponents but don't know how i can algebraically express how to solve it??

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2That's it now just factor

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No, remember how you factor, what two numbers add up to 1 and multiply to give 6, those are your two factors.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2There we go, so our roots are x = 3, and x = 2 :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! but we omit 2 because the natural logs domain is from (0,oo) right?
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