anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
How can you solve this algebraically ln(x2-x) =ln 6
anonymous
  • anonymous
well both arguments should be the same, just equal both and solve the equation
anonymous
  • anonymous
x^2-x = 6 i know the answer is 3 but don't know how to express it algebraically

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Astrophysics
  • Astrophysics
Hint: \[\huge e^{lnx} = x\]
anonymous
  • anonymous
Well I'm using the one to one property of exponents but don't know how i can algebraically express how to solve it??
anonymous
  • anonymous
x^2 -x =6
Astrophysics
  • Astrophysics
That's it now just factor
Astrophysics
  • Astrophysics
No, remember how you factor, what two numbers add up to -1 and multiply to give -6, those are your two factors.
anonymous
  • anonymous
(x-3) (x+2)
anonymous
  • anonymous
x=3 x=-2
Astrophysics
  • Astrophysics
There we go, so our roots are x = 3, and x = -2 :)
anonymous
  • anonymous
Thanks! but we omit -2 because the natural logs domain is from (0,oo) right?
Astrophysics
  • Astrophysics
Yes :)

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