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anonymous
 one year ago
For this question, does it mean that I can use the Fundamental Theory of Calculus? Or is this question looking for a different kind of solution?
anonymous
 one year ago
For this question, does it mean that I can use the Fundamental Theory of Calculus? Or is this question looking for a different kind of solution?

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5Look at the integrand : \[y = 1+\sqrt{9x^2}\] does that equation look familiar to you ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does it have anything to do with a circle?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've sort of forgotten it... but it does remind me of some stuff :D what am I supposed to do with it then?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You know how to graph \[y = \sqrt{9x^2}\]?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[y = \sqrt{r^2x^2}\] this is the top of a circle right c(0,0) so your radius is \[y=\sqrt{3^2x^2}\] with centre (0,)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437032388863:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh so its a semicircle, going from 3 to 3, ok got it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, thank god for ganeshies drawing, mine was horrible, but notice the +1 means it shifts 1 unit up vertically.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437032757654:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thats a great drawing! Thanks so much @ganeshie8! So now I can use the idea of summing the area of rectangles to find the area under the curve from 3 to 0, right?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5Really ? how about simply using the area of circle formula ?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yeah you could just use quarter of a circle area xD

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[A = \frac{ 1 }{ 4 } \pi r^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh yeah!! xD i was going the hard way!! True true true!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1and the area of the rectangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But then, does that still work when it has shifted a unit up?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437033158066:dw