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anonymous
 one year ago
FAN+MEDAL+TESTIMONIAL:):)!!
How many arrangements are there of the word MATHEMATICS?
How many of these start with the letter M?
How many of the arrangements in part a have the T’s together?
anonymous
 one year ago
FAN+MEDAL+TESTIMONIAL:):)!! How many arrangements are there of the word MATHEMATICS? How many of these start with the letter M? How many of the arrangements in part a have the T’s together?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think that this is a permutation problem. So given that there are 11 letters in the word math, I will do the following calculation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Without restrictions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Am I on the right track?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ya know I'm stuck on this question right now too :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a university level math don't worryXD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:O really? its on my 8th grade quiz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Forgive me I am in a Canadian school.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol ok i will try to help tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Arrangement of letters of a word is a permutation question right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As opposed to combination

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Am I on the right track?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How many arrangements are there of the word MATHEMATICS? Rule: Start with the factorial of the number of letters in the word. Then, for each indistinguishable letter in the word, divide by the factorial of the number of times that letter occurs in the word. "MATHEMATICS" is an 11letter word. If all the letters were distinguishable like in "MATHEmatICS", the answer would be 11! = 39916800 However, there are 2 indistinguishable M's 2 indistinguishable A's 2 indistinguishable T's Thus, using the rule, we divide 11! by (2!)(2!)(2!) \[\frac{ 11! }{ 2!*2!*2! }=\frac{ 39916800 }{ 8 }=4989600\] How many of these start with the letter M? That amounts to finding all the distinguishable arrangements of the 10letter "word" "ATHEMATICS" and putting an M in the beginning of each. "ATHEMATICS" is a 10letter "word" and it contains 2 indistinguishable A's 2 indistinguishable T's Thus, using the rule, we divide 10! by (2!)(2!) \[\frac{ 10! }{ 2!*2! }=\frac{ 3628800 }{ 4 }=907200\] How many of the arrangements in part a have the T’s together? That amounts to finding all the distinguishable arrangements of the 10letter "word" "MATHEMAICS" and inserting another T to the right of the "T" in each. "MATHEMAICS" is a 10letter "word" and it contains 2 indistinguishable M's 2 indistinguishable A's Thus, using the rule, it's exactly the same answer as the second part. We divide 10! by (2!)(2!) \[\frac{ 10! }{ 2!*2! }=\frac{ 3628800 }{ 4 }=907200\] There ya go!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let me know if it could be better
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