FAN+MEDAL+TESTIMONIAL:):)!! How many arrangements are there of the word MATHEMATICS? How many of these start with the letter M? How many of the arrangements in part a have the T’s together?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

FAN+MEDAL+TESTIMONIAL:):)!! How many arrangements are there of the word MATHEMATICS? How many of these start with the letter M? How many of the arrangements in part a have the T’s together?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I think that this is a permutation problem. So given that there are 11 letters in the word math, I will do the following calculation
11P11
Without restrictions

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

hai
Hi Sir:)
Am I on the right track?
ya know I'm stuck on this question right now too :P
This is a university level math don't worryXD
:O really? its on my 8th grade quiz
Forgive me I am in a Canadian school.
lol ok i will try to help tho
gimee a sec
Arrangement of letters of a word is a permutation question right?
As opposed to combination
Hi everyone:)
Am I on the right track?
I don't know.
How many arrangements are there of the word MATHEMATICS? Rule: Start with the factorial of the number of letters in the word. Then, for each indistinguishable letter in the word, divide by the factorial of the number of times that letter occurs in the word. "MATHEMATICS" is an 11-letter word. If all the letters were distinguishable like in "MATHEmatICS", the answer would be 11! = 39916800 However, there are 2 indistinguishable M's 2 indistinguishable A's 2 indistinguishable T's Thus, using the rule, we divide 11! by (2!)(2!)(2!) \[\frac{ 11! }{ 2!*2!*2! }=\frac{ 39916800 }{ 8 }=4989600\] How many of these start with the letter M? That amounts to finding all the distinguishable arrangements of the 10-letter "word" "ATHEMATICS" and putting an M in the beginning of each. "ATHEMATICS" is a 10-letter "word" and it contains 2 indistinguishable A's 2 indistinguishable T's Thus, using the rule, we divide 10! by (2!)(2!) \[\frac{ 10! }{ 2!*2! }=\frac{ 3628800 }{ 4 }=907200\] How many of the arrangements in part a have the T’s together? That amounts to finding all the distinguishable arrangements of the 10-letter "word" "MATHEMAICS" and inserting another T to the right of the "T" in each. "MATHEMAICS" is a 10-letter "word" and it contains 2 indistinguishable M's 2 indistinguishable A's Thus, using the rule, it's exactly the same answer as the second part. We divide 10! by (2!)(2!) \[\frac{ 10! }{ 2!*2! }=\frac{ 3628800 }{ 4 }=907200\] There ya go!
YOU ROCK:)
:)
ok testimonial?
let me know if it could be better

Not the answer you are looking for?

Search for more explanations.

Ask your own question