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anonymous
 one year ago
Find dy/dx of ln(xy)sqrt(x)=sqrt(y)
Please help me understand this.
anonymous
 one year ago
Find dy/dx of ln(xy)sqrt(x)=sqrt(y) Please help me understand this.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0go @Haseeb96 bhhaiya go

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.2ap kar rahi ho help is ki

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0noo u have misunderstanding ur doing it

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.2dw:1437043335188:dw

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.2dw:1437043606231:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks bhai. hum bhi ek time india mein parhai karte te.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \displaystyle \ln(xy)\sqrt{x}=\sqrt{y} }\) simplify. \(\large\color{black}{ \displaystyle \ln(x)\ln(y)\sqrt{x}=\sqrt{y} }\)\ differentiate (dy/dx) \(\large\color{black}{ \displaystyle \frac{1}{x}\frac{y' }{y}\frac{1}{2\sqrt{x}}=\frac{y'}{2\sqrt{x}} }\) isolate the terms with y' on one side. \(\large\color{black}{ \displaystyle \frac{1}{x}\frac{1}{2\sqrt{x}}=\frac{y'}{2\sqrt{x}}+\frac{y' }{y} }\) factor out of y' \(\large\color{black}{ \displaystyle \frac{1}{x}\frac{1}{2\sqrt{x}}=\left(\frac{1}{2\sqrt{x}}+\frac{1}{y} \right)y'}\) common denominators on both sides \(\large\color{black}{ \displaystyle \frac{2}{2x}\frac{\sqrt{x}}{2x}=\left(\frac{y}{2y\sqrt{x}}+\frac{2\sqrt{x}}{2y\sqrt{x}} \right)y'}\) adding/subtracting \(\large\color{black}{ \displaystyle \frac{2\sqrt{x}}{2x}=\left(\frac{y+2\sqrt{x}}{2y\sqrt{x}} \right)y'}\) isolateing the y' (entirely) \(\large\color{black}{ \displaystyle {\LARGE \frac{\frac{2\sqrt{x}}{2x}}{\frac{y+2\sqrt{x}}{2y\sqrt{x}}} }=y'}\) simplifying further \(\large\color{black}{ \displaystyle \frac{(2\sqrt{x})~2y\sqrt{x} }{2x~(y+2\sqrt{x})}=y'}\) 2's cancel \(\large\color{black}{ \displaystyle \frac{(2\sqrt{x})~y\sqrt{x} }{x~(y+2\sqrt{x})}=y'}\) You can play around more, but I would leave it as it is right now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this made alot of sense, I will go back into the book so im 100% on this. thanks:)
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