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anonymous
 one year ago
MEDAL&FAN&Testimonials
(nr+1)!/(nr2)!
How do I write this without using factorial notation?
anonymous
 one year ago
MEDAL&FAN&Testimonials (nr+1)!/(nr2)! How do I write this without using factorial notation?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My head's stuck on this problem if anyone could offer me help that would be awesome!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 the almighty?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to do this problem?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Hint : let \(nr+1 = m\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The trickiest part is that denominator is negative whereas the numerator is positive.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This makes me feel insecure about canceling either.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(m)(m1)(m2)/(m3)(m4)(m5)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{(nr+1)!}{(nr2)!} = \dfrac{(\color{blue}{nr+1})!}{(\color{blue}{nr+1}3)!} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Looks like the factorials are all canceled but (3)!, at least intuitively.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Let that blue part equal \(\color{blue}{m}\) : \[\dfrac{(nr+1)!}{(nr2)!} = \dfrac{(\color{blue}{nr+1})!}{(\color{blue}{nr+1}3)!} =\dfrac{\color{blue}{m}!}{(\color{blue}{m}3)!} =mP3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How come mP3 and not 1/3!?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1recall the definition of permutation : \[nPr = \dfrac{n!}{(nr)!}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not the conventional calculation of fractions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Assuming that rule, (n+4)!/(n+2)! will be not (n+4)(n+3)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(n+4)(n+3)(n+2)(n+1)(n)/(n+2)(n+1)(n)=(n+4)(n+3)? This is not correct?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{(n+4)(n+3)(n+2)(n+1)(n)}{(n+2)(n+1)(n)}\] cancel like terms should be (n+4)(n+3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0At first seemed a bit counterintuitive after what Ganashie showed me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I guess I am not so retarded at this timeXD
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