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anonymous
 one year ago
So I need to arrange 4 science books and 3 math books in such manner that science books are together and math books are together laying on top va each other. How many ways I can do this?
anonymous
 one year ago
So I need to arrange 4 science books and 3 math books in such manner that science books are together and math books are together laying on top va each other. How many ways I can do this?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Me thinks 4*3*2*1+3*2*1=30

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0This is a combination. What is 4 times 3?

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0That is the number of different ways you can change the way they are situated

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1This is what I think. There are 4P4 ways to rearrange the science books, AND there are 3P3 ways to rearrange the math books. And all books have to be on top of each other, would mean either math books on top of science books, or science books on top of math books. that means that all your previous permutations should be multiplied times two.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1it should end up pretty big (not 12 or 11)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok but answer says 288!!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no entiendo por nada!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes, because you multiply the permuations by math books, times the permutations by science books

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1and then multiply by two, because math books can be on top of sceince books or vv

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\left({\rm 4P4}\times {\rm 3P3}\right)\times 2\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1for each permutation of math books, there is all permutations of science books, and vice versa. that is why you multiply.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1and then ×2, because either math books can be on top of science, or the other way around.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to be careful who I ask

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0people misinformed all the time

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Lol, not really....:) thanks tho:)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, sometimes answer is wrong, but you have to do a little analysis if the answer makes sense or not.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1In this case, for example. How can answer be 11 or 12, if the number of combinations of just the science books alone exceeds that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. I was nearly running away with 12 which would be a not so correct but intuitive answer.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1see what I posted about 11 and 12 just now?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1i will rephrase, there is a typo....

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1combinations should be "permutations"

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1But, in any case, now you know.... check your answer to make sense:)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1have a good one!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much! I'll be writing about you
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