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anonymous
 one year ago
An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = 16t2 + 80t + 200, where t represent the time in seconds.
anonymous
 one year ago
An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = 16t2 + 80t + 200, where t represent the time in seconds.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you need help with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = 16t2 + 80t + 200, where t represent the time in seconds. this question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right. But there would be more questions concerning that question you just typed.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You know the equation and everything that's great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which time is specified? I bet you are left to use the formula to calculate the height of the object at certain time following the launch

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to find the Maximum

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is the point at which the parabola reflects.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have an access to online calculator or would you like me to do it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would like you to show me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am on it just a sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Type that into desmos calculator. You should get a vertex of (2.5,300)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's saying that after 2.5 seconds from the launch the height of the object reaches 300m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did you get it or not?
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