An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = -16t2 + 80t + 200, where t represent the time in seconds.

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An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = -16t2 + 80t + 200, where t represent the time in seconds.

Mathematics
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Howdy my friend
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An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. The height of the object, h(t), is modeled by the function h(t) = -16t2 + 80t + 200, where t represent the time in seconds. this question
Right. But there would be more questions concerning that question you just typed.
You know the equation and everything that's great
Which time is specified? I bet you are left to use the formula to calculate the height of the object at certain time following the launch
I have to find the Maximum
Let's graph.
ok
Find the vertex.
That is the point at which the parabola reflects.
Do you have an access to online calculator or would you like me to do it?
I would like you to show me
I am on it just a sec
ok
y=-16t ^ 21+80t+200
Type that into desmos calculator. You should get a vertex of (2.5,300)
It's saying that after 2.5 seconds from the launch the height of the object reaches 300m
Did you get it or not?
yes
so is 300m

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