What is the equation of a line passing through (-3, 7) and having a slope of -1/5? A. y=-5x+22 B. y=5x+22 C. y=1/5x + 32/5 D. y=-1/5x+32/5 E. y=-1/5x+22

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What is the equation of a line passing through (-3, 7) and having a slope of -1/5? A. y=-5x+22 B. y=5x+22 C. y=1/5x + 32/5 D. y=-1/5x+32/5 E. y=-1/5x+22

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We use the point slope formula \[\huge~\rm~y-y_1=m(x-x_1)\] where m=slope (x1,y1)
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^or that

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ok lol i'll try that
b=51/5?
I dont know how to do it this way....
We use the point slope formula \[\huge~\rm~y-y_1=m(x-x_1)\] where m=slope (x1,y1)
Try my way :P
ok i'll try your way
what do i plug in for the variables?
M=slope so -1/5 x1=-3 y1=7
k
i m sorry i cant find a solution im not good at this kinda stuff
\[\huge~\rm~y-7=-1/5(x-(-3)\]
1st step distribute the -1/5 \(\huge\rm\color{red}{-1/5}{(x+3)}\)
ok then what?
Multiply.... ? -1/5 * x =? -1/5 * 3 = ?
-x/5?
Add 7 to both sides. y−7+7=−1/5x+−3/5+7
Once you do that y=−1/5x+32/5
Do you understand?
yes i do thank you so much for your help
No problem :) let me know if you need more help ^-^ Welcome to openstudy! :D

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