## anonymous one year ago What is the equation of a line passing through (-3, 7) and having a slope of -1/5? A. y=-5x+22 B. y=5x+22 C. y=1/5x + 32/5 D. y=-1/5x+32/5 E. y=-1/5x+22

1. pooja195

We use the point slope formula $\huge~\rm~y-y_1=m(x-x_1)$ where m=slope (x1,y1)

2. triciaal

|dw:1437056639003:dw|

3. pooja195

^or that

4. anonymous

ok lol i'll try that

5. anonymous

b=51/5?

6. pooja195

I dont know how to do it this way....

7. pooja195

We use the point slope formula $\huge~\rm~y-y_1=m(x-x_1)$ where m=slope (x1,y1)

8. pooja195

Try my way :P

9. anonymous

10. anonymous

what do i plug in for the variables?

11. pooja195

M=slope so -1/5 x1=-3 y1=7

12. anonymous

k

13. anonymous

i m sorry i cant find a solution im not good at this kinda stuff

14. pooja195

$\huge~\rm~y-7=-1/5(x-(-3)$

15. pooja195

1st step distribute the -1/5 $$\huge\rm\color{red}{-1/5}{(x+3)}$$

16. anonymous

ok then what?

17. pooja195

Multiply.... ? -1/5 * x =? -1/5 * 3 = ?

18. anonymous

-x/5?

19. pooja195

Add 7 to both sides. y−7+7=−1/5x+−3/5+7

20. pooja195

Once you do that y=−1/5x+32/5

21. pooja195

Do you understand?

22. anonymous

yes i do thank you so much for your help

23. pooja195

No problem :) let me know if you need more help ^-^ Welcome to openstudy! :D