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anonymous

  • one year ago

What is the solution to the rational equation ?

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  1. anonymous
    • one year ago
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    |dw:1437056911114:dw|

  2. anonymous
    • one year ago
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    @pooja195 @LynFran @Calcmathlete @JasonWright

  3. anonymous
    • one year ago
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    I got 2 as an answer but I may be wrong.

  4. Loser66
    • one year ago
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    I want to see the original problem. Can you take a pic, scan or snapshot??

  5. anonymous
    • one year ago
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    I tried that already, it didn't work. Do you want me to write it neater?

  6. Loser66
    • one year ago
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    Yes, please. The problem only, not your work

  7. anonymous
    • one year ago
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    That was the problem that I wrote

  8. anonymous
    • one year ago
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    |dw:1437057442794:dw|

  9. Loser66
    • one year ago
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    You meant: Solve for x \[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1}\]

  10. anonymous
    • one year ago
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    Yes :)!

  11. anonymous
    • one year ago
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    Ok so i got 7/2 as an answer, not 2. I meant to say 7/2 :)

  12. Loser66
    • one year ago
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    ok, Yes, I got 7/2 also.

  13. Loser66
    • one year ago
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    And it is a correct answer since I check back \[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1} \\ \dfrac{7/2}{2(7/2)-1}-\dfrac{1}{4}=\dfrac{2}{2(7/2)-1}\]

  14. anonymous
    • one year ago
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    :) Yay!

  15. Loser66
    • one year ago
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    You may make mistake at somewhere when you got 2 as solution.

  16. Loser66
    • one year ago
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    NNNNNNNNNNNNNNNNo

  17. anonymous
    • one year ago
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    I got 2x-5, with a restriction of 5/2. Yes?

  18. Loser66
    • one year ago
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    \[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1}\] \[\dfrac{x}{2x-1}-\dfrac{2}{2x-1}=\dfrac{1}{4}\]

  19. Loser66
    • one year ago
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    \[\dfrac{x-2}{2x-1}=\dfrac{1}{4}\]

  20. Loser66
    • one year ago
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    4(x-2) = 2x-1 4x-8 =2x-1 2x=7 x=7/2

  21. Loser66
    • one year ago
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    I have to go now. Take time to digest it. Good luck

  22. anonymous
    • one year ago
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    :) tHANKS<3

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