What is the solution to the rational equation ?

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What is the solution to the rational equation ?

Mathematics
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|dw:1437056911114:dw|
I got 2 as an answer but I may be wrong.

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I want to see the original problem. Can you take a pic, scan or snapshot??
I tried that already, it didn't work. Do you want me to write it neater?
Yes, please. The problem only, not your work
That was the problem that I wrote
|dw:1437057442794:dw|
You meant: Solve for x \[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1}\]
Yes :)!
Ok so i got 7/2 as an answer, not 2. I meant to say 7/2 :)
ok, Yes, I got 7/2 also.
And it is a correct answer since I check back \[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1} \\ \dfrac{7/2}{2(7/2)-1}-\dfrac{1}{4}=\dfrac{2}{2(7/2)-1}\]
:) Yay!
You may make mistake at somewhere when you got 2 as solution.
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I got 2x-5, with a restriction of 5/2. Yes?
\[\dfrac{x}{2x-1}-\dfrac{1}{4}=\dfrac{2}{2x-1}\] \[\dfrac{x}{2x-1}-\dfrac{2}{2x-1}=\dfrac{1}{4}\]
\[\dfrac{x-2}{2x-1}=\dfrac{1}{4}\]
4(x-2) = 2x-1 4x-8 =2x-1 2x=7 x=7/2
I have to go now. Take time to digest it. Good luck
:) tHANKS<3

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