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anonymous
 one year ago
What is the simplified form of 4x^225/2x5?
anonymous
 one year ago
What is the simplified form of 4x^225/2x5?

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: we can factorize the numerator as follows: \[\Large \frac{{4{x^2}  25}}{{2x  5}} = \frac{{\left( {2x  5} \right)\left( {2x + 5} \right)}}{{2x  5}} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since in general we have: \[\Large {a^2}{x^2}  {b^2} = \left( {ax  b} \right)\left( {ax + b} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What would the restriction be?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since we can not divide by zero, then we have to exclude those values of x such that: \[\Large 2x  5 = 0\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to exclòude x=5/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I was wrong when I said 5/2?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! since \[2x  5 = 0\] when: x=5/2

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please try to solve that equation: 2x5=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok! I see! So the answer would be 2x+5, with a restriction of 5/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:)!!! May I ask another?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the simplifed form of dw:1437058472772:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we can write your division, as a multiplication of the first fraction, times the inverse of the second fraction, like below: \[\Large \begin{gathered} \frac{{x + 1}}{{{x^2} + x  6}}:\frac{{{x^2} + 5x + 4}}{{x  2}} = \hfill \\ \hfill \\ = \frac{{x + 1}}{{{x^2} + x  6}} \cdot \frac{{x  2}}{{{x^2} + 5x + 4}} \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now we have to factorize the subsequent polynomials: \[\Large \begin{gathered} {x^2} + x  6 \hfill \\ {x^2} + 5x + 4 \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+2)(x3) for the first one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+1)(x+4) for the second one

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry, for first trinomial I got this: \[{x^2} + x  6 = \left( {x  2} \right)\left( {x + 3} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whoops yes:) you are right!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, substituting our factorizations, in our computation, we get: \[\Large \begin{gathered} \frac{{x + 1}}{{{x^2} + x  6}}:\frac{{{x^2} + 5x + 4}}{{x  2}} = \hfill \\ \hfill \\ = \frac{{x + 1}}{{{x^2} + x  6}} \cdot \frac{{x  2}}{{{x^2} + 5x + 4}} = \hfill \\ \hfill \\ = \frac{{x + 1}}{{\left( {x  2} \right)\left( {x + 3} \right)}} \cdot \frac{{x  2}}{{\left( {x + 1} \right)\left( {x + 4} \right)}} = ...? \hfill \\ \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Robin can mow a lawn in 3 hours, while Brady can mow the same lawn in 4 hours. How many hours would it take for them to mow the lawn together?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a. 7/12 b. 12/7 c. 12 d. 7

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1If I call with W the work to be done, then the working rate of Robin is W/3, whereas the working rate of Brady is W/4

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, when Robin and brady work together, then the working rate is: \[\Large \frac{W}{3} + \frac{W}{4}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, we can write this equation: \[\Large \left( {\frac{W}{3} + \frac{W}{4}} \right)t = W\] where t is the requested time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand! Continue:) And then find like denominators

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1after a simplification at the left side, we can write: \[\Large \frac{{4W + 3W}}{{12}}t = W\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: we can simplify the left side, so we get: \[\Large \frac{{7W}}{{12}}t = W\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:) Would that be the answer?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, please we can simplify further that equation, and we get this: \[\Large \frac{7}{{12}}t = 1\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now I multiply both sides by 12: dw:1437059913299:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH! Lol I'm sorry! I must have missed that.
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