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AmTran_Bus

  • one year ago

Derivative

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  1. AmTran_Bus
    • one year ago
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    |dw:1437059971490:dw|

  2. AmTran_Bus
    • one year ago
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    So I know the answer (divided all terms on top my u^2), but is there a way I could have just brought the u^2 on the top?

  3. AmTran_Bus
    • one year ago
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    For example, like 1/s = s^-1, right?

  4. welshfella
    • one year ago
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    yes

  5. ganeshie8
    • one year ago
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    sure you can, but why would you wanto do that ?

  6. AmTran_Bus
    • one year ago
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    Its been awhile since algebra and I'm trying to review two different things at once. Can you show me?

  7. ganeshie8
    • one year ago
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    \[\large \dfrac{1}{x^n} = x^{-n}\]

  8. AmTran_Bus
    • one year ago
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    So just make it 5u^-2?

  9. ganeshie8
    • one year ago
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    For the last term, yes

  10. AmTran_Bus
    • one year ago
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    Ok, So here is the soln manual answer: 4y^3-2-10u^-3 If I did it this way, I would get 6u^5-6u^2-10u^-3?

  11. AmTran_Bus
    • one year ago
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    So how is that the same?

  12. AmTran_Bus
    • one year ago
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    Not 4y, 4u.

  13. ganeshie8
    • one year ago
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    They are not same. Show me how you arrived at that answer of yours

  14. ganeshie8
    • one year ago
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    Aren't you dividing the bottom by each term in the top ? |dw:1437060429901:dw|

  15. AmTran_Bus
    • one year ago
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    |dw:1437060422214:dw|

  16. AmTran_Bus
    • one year ago
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    Right, the way you did it is the way the soln man said.

  17. ganeshie8
    • one year ago
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    \[\dfrac{a+b+c}{n} = \dfrac{a}{n}+\dfrac{b}{n}+\dfrac{c}{n}\]

  18. AmTran_Bus
    • one year ago
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    I understand it that way. So you simply just can't only do 5u^-2 on this one. Ok.

  19. ganeshie8
    • one year ago
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    There is no such rule. \[\dfrac{a+b+c}{n} \color{Red}{\ne} a+b+\dfrac{c}{n}\]

  20. AmTran_Bus
    • one year ago
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    Thanks so much! Got it!

  21. ganeshie8
    • one year ago
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    np

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