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|dw:1437061349807:dw|

I got 15/7

Is the first fraction x/(x^2-4)?

ok give me a minute to check your answer

ok:)

well done! that's correct

yay! Will you check another?

yep!

I got 13/2

a. 13/2
b. 1
c. 4
d. 15/2

ok give me a sec

kk

I dont get any of those choices?

i posted them up there hold on.

a. 13/2
b. 1
c. 4
d. 15/2

what i meant was that I dont get any of the choices you posted?

oh! I know, I don't understand either.

could be a typo?

|dw:1437062887584:dw|

Solve for x and determine if the solution is extraneous or not.

no, it's a dumb question. Can we do this one instead?

I got 3, non-extraneous

Ok. So for the previous question, i got 15/2 ?

Yep! thats it
let me check the 3rd question

kk

Oh! Thanks:)

|dw:1437063265629:dw|

Last one because I have no idea how to solve this one but I got 1/3x

is that x^2 on the top and x^5 on the bottom?

x^2 on the top and x^3 on the bottom

It goes like this
\[\frac{ 1/x ^{2} }{3/x ^{3} } = \frac{ 1 }{ x ^{2} }.\frac{ x ^{3} }{ 3 }\]

can you do the rest?

x^3/3x^2

No. I'll go a bit further..........
\[= \frac{ x ^{3} }{ 3x ^{2}}\]

now what do you get?

x/3x

here are the rules of exponents
\[\frac{ x ^{a} }{ x ^{b} } = x ^{a-b}\]

So then I assume it would be 3x

No, the three stays on the bottom line

Then it would just be 3/x

sorry, x/3

yeah thats it

Yay! Thanks so much! <3

No problem. I enjoyed helping you out

you're a good student

Thanks:)