What is the solution to the rational equation ?
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- anonymous

What is the solution to the rational equation ?
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- anonymous

|dw:1437061349807:dw|

- anonymous

@Study_together

- anonymous

@Michele_Laino

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## More answers

- anonymous

I got 15/7

- alekos

Is the first fraction x/(x^2-4)?

- anonymous

no it is x/(x^2-9) @alekos

- alekos

ok give me a minute to check your answer

- anonymous

ok:)

- alekos

well done! that's correct

- anonymous

yay! Will you check another?

- alekos

yep!

- anonymous

Dominique can ice cupcakes twice as fast as Houston. When they work together, Dominique and Houston can ice a large order of cupcakes in 5 hours. How many hours would it take Houston to ice them by himself?

- anonymous

I got 13/2

- anonymous

a. 13/2
b. 1
c. 4
d. 15/2

- alekos

ok give me a sec

- anonymous

kk

- alekos

I dont get any of those choices?

- anonymous

i posted them up there hold on.

- anonymous

a. 13/2
b. 1
c. 4
d. 15/2

- alekos

what i meant was that I dont get any of the choices you posted?

- anonymous

oh! I know, I don't understand either.

- alekos

could be a typo?

- anonymous

|dw:1437062887584:dw|

- anonymous

Solve for x and determine if the solution is extraneous or not.

- anonymous

no, it's a dumb question. Can we do this one instead?

- anonymous

I got 3, non-extraneous

- alekos

with the previous question I think it should be "how long would it take dominique on his own" Then you would get one of those choices

- anonymous

Ok. So for the previous question, i got 15/2 ?

- alekos

Yep! thats it
let me check the 3rd question

- anonymous

kk

- alekos

it is 3 but it would be classed as extraneous because if you substitute this in the original fractions you get zero on the bottom line

- anonymous

Oh! Thanks:)

- anonymous

|dw:1437063265629:dw|

- anonymous

Last one because I have no idea how to solve this one but I got 1/3x

- alekos

is that x^2 on the top and x^5 on the bottom?

- anonymous

x^2 on the top and x^3 on the bottom

- alekos

It goes like this
\[\frac{ 1/x ^{2} }{3/x ^{3} } = \frac{ 1 }{ x ^{2} }.\frac{ x ^{3} }{ 3 }\]

- alekos

can you do the rest?

- anonymous

@alekos I got 1/3x

- anonymous

x^3/3x^2

- alekos

No. I'll go a bit further..........
\[= \frac{ x ^{3} }{ 3x ^{2}}\]

- alekos

now what do you get?

- anonymous

x/3x

- alekos

here are the rules of exponents
\[\frac{ x ^{a} }{ x ^{b} } = x ^{a-b}\]

- anonymous

So then I assume it would be 3x

- alekos

No, the three stays on the bottom line

- anonymous

Then it would just be 3/x

- anonymous

sorry, x/3

- alekos

yeah thats it

- anonymous

Yay! Thanks so much! <3

- alekos

No problem. I enjoyed helping you out

- alekos

you're a good student

- anonymous

Thanks:)

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