Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two values. A)The value of g(−2) is larger than the value of g(4). B)The value of g(−2) is the same as the value of g(4). C)The value of g(−2) is smaller than the value of g(4). D)The values of g(−2) and g(4) cannot be compared.

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Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two values. A)The value of g(−2) is larger than the value of g(4). B)The value of g(−2) is the same as the value of g(4). C)The value of g(−2) is smaller than the value of g(4). D)The values of g(−2) and g(4) cannot be compared.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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to find g(-2), plug in -2 instead of x, into the function g(x).
Same way, to find g(4), plug in 4 instead of x (into the same function).

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Other answers:

I NEED to find?
we need to find to find the value of g(-2) and g(4) first okay what we will do for it first plug -2 at the place of x in the given equation you will get g(-2) = -18 now plug or put 4 at the place of x , you will get g(4) = 30
now compare it we get that the value of g(-2) is less than g(4) because g(-2) = -18 and g(4) =30 . I hope you get it if you have any other question regarding my explanation ask me freely. thank you
oh wait so the answer its D?
no , Answer will be C

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