Pre-image point N(6, -3) was dilated to point N'(2, -1). What was the scale factor used? 1/2 1/3 3 2

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Pre-image point N(6, -3) was dilated to point N'(2, -1). What was the scale factor used? 1/2 1/3 3 2

Mathematics
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When you're dealing with scale factors, you're multiply the the pre-image by a number to get the image. So, we get \((N'(2,-1)=N(6k,-3k)\) where k is the scale factor. Can you figure it out from here (aka solve for k)?

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Other answers:

uhh
Ok, to make it a bit simpler, we need to solve for the value of k that would satisfy the equations \[2=6k\]AND\[-1=-3k\]Does that help?
yeah
@imqwerty @Calcmathlete alittle more help please
1.3?
Let's start with the first equation first. How do you solve 6k = 2?
/3
Well, you're trying to get k by itself. k is multiplied by 6, to get rid of it, you divide by 6. on both sides.\[\frac{6k}{6}=\frac26\]\[k=???\]
1/3!
...
yes!!!!!!! you got it
good job i gave you a medal
Yup! k=1/3. You want to make sure that you got the number right, so plug it back in to see if it is correct. When you do plug it in, you see that k works for both equations, and you found the scale factor. :)
we have pre image point =(6, -3) and we hav new point = (2,-1) scale factor is the number multiplied with the pre image point (6,-3) to get the new point (2,-1) lets take the scale factor as m so (6m,-3m)=(2,-1) so 6m=2 frm here we get m=1/3 and also -3m=-1 frm here we get m=1/3 so scale factor is 1/3
<3

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