## anonymous one year ago Pre-image point N(6, -3) was dilated to point N'(2, -1). What was the scale factor used? 1/2 1/3 3 2

1. anonymous

@imqwerty

2. anonymous

@AG23

3. anonymous

When you're dealing with scale factors, you're multiply the the pre-image by a number to get the image. So, we get $$(N'(2,-1)=N(6k,-3k)$$ where k is the scale factor. Can you figure it out from here (aka solve for k)?

4. anonymous

uhh

5. anonymous

Ok, to make it a bit simpler, we need to solve for the value of k that would satisfy the equations $2=6k$AND$-1=-3k$Does that help?

6. anonymous

yeah

7. anonymous

@imqwerty @Calcmathlete alittle more help please

8. anonymous

1.3?

9. anonymous

Let's start with the first equation first. How do you solve 6k = 2?

10. anonymous

/3

11. anonymous

Well, you're trying to get k by itself. k is multiplied by 6, to get rid of it, you divide by 6. on both sides.$\frac{6k}{6}=\frac26$$k=???$

12. anonymous

1/3!

13. anonymous

...

14. thehumantorch10

yes!!!!!!! you got it

15. thehumantorch10

good job i gave you a medal

16. anonymous

Yup! k=1/3. You want to make sure that you got the number right, so plug it back in to see if it is correct. When you do plug it in, you see that k works for both equations, and you found the scale factor. :)

17. imqwerty

we have pre image point =(6, -3) and we hav new point = (2,-1) scale factor is the number multiplied with the pre image point (6,-3) to get the new point (2,-1) lets take the scale factor as m so (6m,-3m)=(2,-1) so 6m=2 frm here we get m=1/3 and also -3m=-1 frm here we get m=1/3 so scale factor is 1/3

18. anonymous

<3