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anonymous

  • one year ago

Please help! i will fan and medal! θ is in Quadrant III and cos^2(θ)=1/4 A. Evaluate cotθ. B. In two or more sentences, explain how to find the value of cotθ.

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  1. anonymous
    • one year ago
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    hey are you single

  2. anonymous
    • one year ago
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    no im not haha @hadewehjsds

  3. anonymous
    • one year ago
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    wow ight

  4. anonymous
    • one year ago
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    im sorry to say but MARIO

  5. anonymous
    • one year ago
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    Square root both the sides, after that you will get 2 values for cos theta, a positive and a negative value but you are given theta in in 3rd quadrant so use that fact to figure out the right value For reference: In 1st Quadrant all trig functions are positive In 2nd only sine and cosecant are positive In 3rd only tangent and cotangent are positive In 4th only cosine secant are positive A good mnemonic to remember is After School To College A for all postive S for sine and it's reciprocal positive T for tangent and it's reciprocal positive C for cosine and it's reciprocal positive

  6. anonymous
    • one year ago
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    okay so cos(θ)=1/2. how does that help me know what cotθ is? @Nishant_Garg

  7. anonymous
    • one year ago
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    Are you sure it's 1/2 and not -1/2?? Check carefully, After that if you remember your trig table the values of 30, 45, 60, 90 for your trig functions u should be able to find your angle and then use the same table to find cot theta Really it's more of a memory game here

  8. anonymous
    • one year ago
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    mario im random

  9. anonymous
    • one year ago
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    i dont know what trig table you are talking about @Nishant_Garg

  10. anonymous
    • one year ago
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    Basically trig values for the angles 30, 45, 60, 90 are somewhat basic and you should remember them for at least sine cos tan so really it's easy if u remember the values u can clearly tell which angle it is

  11. anonymous
    • one year ago
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    or u can use a calculator if u r allowed

  12. princeharryyy
    • one year ago
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    |dw:1437072680945:dw|

  13. anonymous
    • one year ago
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    First tell me if you have figured out the correct equation \[\cos(\theta)=\frac{1}{2}\] or \[\cos(\theta)=-\frac{1}{2}\] Then I can guide you further

  14. anonymous
    • one year ago
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    \[\cos (\theta)=-1/2\]

  15. anonymous
    • one year ago
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    ok so now you can see how to modify the equation do you know at which angle cos will give 1/2?

  16. anonymous
    • one year ago
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    no i dont @Nishant_Garg

  17. anonymous
    • one year ago
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    ok so cos will give 1/2 at angle 60 degree or in radians pi/3 \[\cos(\theta)=-\cos(60)\] Now here are some formulae's you should know \[\cos(180+\theta)=\cos(180-\theta)=-\cos(\theta)\] Let's add and subtract 180 on the right side angle \[\cos(\theta)=-\cos(60+180-180)\] You can modify it as \[\cos(\theta)=-\cos(180-120)\] Now use the formula \[\cos(180-\theta)=-\cos(\theta)\]\[\cos(\theta)=-(-\cos(120))=\cos(120)\]

  18. anonymous
    • one year ago
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    I actually got a friend to help me. thank you so much for the help! @Nishant_Garg

  19. anonymous
    • one year ago
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    Ah, you're welcome!

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