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anonymous
 one year ago
What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of 8? (5 points)
an = 4(2)n  1; all integers where n ≥ 0
an = 4(2)n  1; all integers where n ≥ 1
an = 4(12)n  1; all integers where n ≥ 1
an = 4(12)n  1; all integers where n ≥ 0
anonymous
 one year ago
What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of 8? (5 points) an = 4(2)n  1; all integers where n ≥ 0 an = 4(2)n  1; all integers where n ≥ 1 an = 4(12)n  1; all integers where n ≥ 1 an = 4(12)n  1; all integers where n ≥ 0

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know it's a or b but i don't know how to find the domain

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2what do you think the common ratio is...? so 4 x r = 8 r = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i told you.. I know it's a or b i just don't know the domain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait no isn't the common ratio 8/4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0bc it's 2nd term divided by first

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2ok... so if you know its a or b look at a and substitute n = 0 into the equation.... what do you get..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well the common ratio is the value you multiply the 1st term by to get the 2nd etc... it can be found by dividing the 2nd term by the 1st term...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2but what happens when you substitute n = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i find the domain is what I'm asking

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08i got your message late lol

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well to find the domain, you have 2 choices... so substitute each choice n =0 into the equation and then n = 1 and see which gives the 1st term of 4

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2so does \[a_{0} = 4\times (2)^{0 1}\] is \[A_{0} = 4\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2lol... no its not a if you do the calculation its \[a_{0} = 4 \times (2)^{1} = 4 \times \frac{1}{2} = 2\] all you needed to do was read the question, you were told \[a_{1} = 4 \] the 1st term was 4 so n = 1 \[a_{1} = 4 \times (2)^{1 1} = 4 \times (2)^0 = 4 \times 1 =4\]
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