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vera_ewing

  • one year ago

For the weak hypochlorous acid (HClO), which statement is true at the point halfway to the equivalence point? A. The total amount of HClO is equal to the pKa. B. The total amount of HClO is equal to ClO-. C. The total amount of H3O+ is equal to the amount of OH- . D. The total amount of ClO- is equal to the Ka of the acid.

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  1. JFraser
    • one year ago
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    the half-equivalence point is a very important point of a titration. If you are titrating exactly 1.00mol of a weak acid with a base like NaOH, once you've added 0.500mol of the \(OH^{-1}\) ion, you've used exactly \(half\) of the acid, right?

  2. vera_ewing
    • one year ago
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    Right, okay.

  3. JFraser
    • one year ago
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    When the general reaction is\[HA + OH^{-1}(aq) \rightarrow A^{-1}(aq) + H_2O\]and if you use an ICE table approach, you get:

  4. JFraser
    • one year ago
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    if you start with 1.00mol of HA, and react half of it, you're left with 0.500mol of acid HA left over, but you've also \(formed\) 0.500mol of the conjugate, \(A^{-1}\)

  5. Rushwr
    • one year ago
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    Hey there I'm not sre with my answer though I'll be telling you my opinion on this ; I will go with the answer 2 or 3

  6. JFraser
    • one year ago
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    it's not C. are you familiar with ICE tables for equilibrium problems?

  7. Rushwr
    • one year ago
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    C or B I"m not sre with that

  8. vera_ewing
    • one year ago
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    It's B?

  9. Photon336
    • one year ago
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    H3O+ and OH- would be the equivalence point pH = pKA + LOG[1] so it's not C

  10. JFraser
    • one year ago
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    at the half-equivalence point, you've used up half of the \(HA\), but formed half of the \(A^{-1}\)

  11. Rushwr
    • one year ago
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    then is it B is what I am asking @Photon336

  12. Photon336
    • one year ago
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    Don't know why I find this confusing if you use up half of the HA and form half of A- then pH = pKA Then at this point the pH = pKA at half equivalence point. Think I mixed it up.

  13. Photon336
    • one year ago
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    If that's true then the amount of HClO = ClO- B

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