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vera_ewing
 one year ago
For the weak hypochlorous acid (HClO), which statement is true at the point halfway to the equivalence point?
A. The total amount of HClO is equal to the pKa.
B. The total amount of HClO is equal to ClO.
C. The total amount of H3O+ is equal to the amount of OH .
D. The total amount of ClO is equal to the Ka of the acid.
vera_ewing
 one year ago
For the weak hypochlorous acid (HClO), which statement is true at the point halfway to the equivalence point? A. The total amount of HClO is equal to the pKa. B. The total amount of HClO is equal to ClO. C. The total amount of H3O+ is equal to the amount of OH . D. The total amount of ClO is equal to the Ka of the acid.

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JFraser
 one year ago
Best ResponseYou've already chosen the best response.1the halfequivalence point is a very important point of a titration. If you are titrating exactly 1.00mol of a weak acid with a base like NaOH, once you've added 0.500mol of the \(OH^{1}\) ion, you've used exactly \(half\) of the acid, right?

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1When the general reaction is\[HA + OH^{1}(aq) \rightarrow A^{1}(aq) + H_2O\]and if you use an ICE table approach, you get:

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1if you start with 1.00mol of HA, and react half of it, you're left with 0.500mol of acid HA left over, but you've also \(formed\) 0.500mol of the conjugate, \(A^{1}\)

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Hey there I'm not sre with my answer though I'll be telling you my opinion on this ; I will go with the answer 2 or 3

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1it's not C. are you familiar with ICE tables for equilibrium problems?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1C or B I"m not sre with that

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0H3O+ and OH would be the equivalence point pH = pKA + LOG[1] so it's not C

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1at the halfequivalence point, you've used up half of the \(HA\), but formed half of the \(A^{1}\)

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1then is it B is what I am asking @Photon336

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Don't know why I find this confusing if you use up half of the HA and form half of A then pH = pKA Then at this point the pH = pKA at half equivalence point. Think I mixed it up.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0If that's true then the amount of HClO = ClO B
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