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anonymous
 one year ago
Whats the sum of the first 50 terms?
\( \huge { 12  \frac{7}{10}n } \)
I am getting \ ( \huge \frac{445}{2} \) is that right because it is stating it is wrong. They stat it is \( \huge \frac{585}{2} \)
I am using \( \huge \frac{n}{2}[2*a_1 + (n1)d) ] to solve\)
anonymous
 one year ago
Whats the sum of the first 50 terms? \( \huge { 12  \frac{7}{10}n } \) I am getting \ ( \huge \frac{445}{2} \) is that right because it is stating it is wrong. They stat it is \( \huge \frac{585}{2} \) I am using \( \huge \frac{n}{2}[2*a_1 + (n1)d) ] to solve\)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Whats the sum of the first 50 terms? \( \huge { 12  \frac{7}{10}n } \) I am getting \ ( \huge \frac{445}{2} \) is that right because it is stating it is wrong. They stat it is \( \huge \frac{585}{2} \) I am using \( \huge \frac{n}{2}[2*a_1 + (n1)d) ] \) to solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge \frac{50}{2}[2*\frac{127}{10} + (501)*\frac{7}{10} ]\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This \( \huge \huge { 12  \frac{7}{10}n }\) SHOULD BE \( \huge\huge { 12  \frac{7}{10}n } \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, so is the sequence \(a_n=12\frac{7}{10}n\), \(n>0\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, if so, I think what you did wrong is that your first term is wrong.\[a_1=12\frac{7}{10}=\frac{113}{10}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah and I got 127/10. Now how did I get 127...... That was the problem.... I hate mis calculating problems lol Thank you. It came up to be correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol np. Everyone makes these kinds of mistakes from time to time. :)
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