A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
+1 medal +1 fan +1 fan testimonial
Given the function f(x) = x2 and k = –3, which of the following represents a vertical shift...
f(x) + k
kf(x)
f(x+k)
f(kx)
anonymous
 one year ago
+1 medal +1 fan +1 fan testimonial Given the function f(x) = x2 and k = –3, which of the following represents a vertical shift... f(x) + k kf(x) f(x+k) f(kx)

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0tititanc help me after

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think about how the graph of y=x looks like compared to y=x+3. How about y=x^2 compared to y=x^27 In general, adding a constant to a function shifts it vertically. Choice b dilates the graph depending on the value of k. If k is a positive real number > 1 the graph will be stretched vertically (and thus compressed horizontally), for example. If k is a number < 1 but > 0, then the graph is compressed vertically and stretched horizontally (it becomes wider) Choice c moves the graph horizontally. Usually it is written as f(xk), where the graph is moved k units. If k is positive, it's to the right, if it's negative (which will cause it to be f(x(k)) = f(x+k)) then it's to the left. Choice d dilates the graph too, but in the opposite way that b does. So if k is a positive real number > 1, then the graph will be dilated **horizontally** by k, but **vertically** by 1/k. In other words, it will be compressed/become wider like in choice b. If k is a number <1 but >0, then the graph is stretched vertically.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.