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I need help. Question is in comments

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Part A: Using the graph above, create a system of inequalities that only contain points D and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points D and E are solutions to the system of inequalities created in Part A. Part C: Timothy can only attend a school in his designated zone. Timothy's zone is defined by y < 3x - 3. Explain how you can identify the schools that Timothy is allowed to attend.
have you tried it yet?

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I have tried it, I am just awful at system of inequalities ..
Do you do the order pair like ( 0, 4 ) & ( 1, 4 )?
no. it'll be better to sepearte the x and y
do you know how to graph an inequality?
lets look at the x- coordiate. what two numbers are D and E between?
1, 0, -1?
J i think I know how to graph inequalities, is that what i have to do here?
pretty much, yes
only thing is youj need the inequalites equations, is all
I'm sorry I am really bad at this .
|dw:1437088210344:dw| now this is where D and E are
|dw:1437088327956:dw| and if you look at the x-coordiate, its somewhere between these two numbers, right?
yes
and how would you write this as an inequaulity?
notice the primary colors recall that yellow and red make green notice where they go about notice those lines use those lines, or those points given, to get the equations for the inequalities
notice that if you use those 2 lines and their shaded "true" regions they intersect on the "green zone", that comprises D and E
yes so um
so... get the equations for those lines first :)
-2+4 < 2+4? I really don't know Im sorry.. Math isn't really my thing ..
well... have you covered "slopes" yet?
yes but its pretty recent I haven't "mastered," it..
ok well... let's ... hmmm seee if we can get the lline equations first notice, the equations for lines AF and lines BC are what we're after one sec
C is the point (2,1) and B is the point (-4,-2) Find the slope of the line joining those two points.
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({\color{red}{ -5}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) F&({\color{red}{ 3}}\quad ,&{\color{blue}{ -4}})\\ B&({\color{red}{ -4}}\quad ,&{\color{blue}{ -2}})\quad % (c,d) C&({\color{red}{ 2}}\quad ,&{\color{blue}{ 1}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\) anyhow... there get the slopes of those, and then get their EQUAtions first so we can get the inequality after
Is there any simpler way of explaining it?
or no? because I could figure it out I would just need time ..
hmmm doubt it, that's... kinda straightforward methinks
ah okie Well then I better get to researching .-.
k
I give up :') thanks guys for trying .

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