I need help. Question is in comments

- anonymous

I need help. Question is in comments

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- anonymous

Part A: Using the graph above, create a system of inequalities that only contain points D and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above.
Part B: Explain how to verify that the points D and E are solutions to the system of inequalities created in Part A.
Part C: Timothy can only attend a school in his designated zone. Timothy's zone is defined by y < 3x - 3. Explain how you can identify the schools that Timothy is allowed to attend.

- anonymous

##### 1 Attachment

- nikato

have you tried it yet?

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- anonymous

I have tried it, I am just awful at system of inequalities ..

- anonymous

Do you do the order pair like ( 0, 4 ) & ( 1, 4 )?

- nikato

no. it'll be better to sepearte the x and y

- jdoe0001

do you know how to graph an inequality?

- nikato

lets look at the x- coordiate.
what two numbers are D and E between?

- anonymous

1, 0, -1?

- anonymous

J i think I know how to graph inequalities, is that what i have to do here?

- jdoe0001

pretty much, yes

- jdoe0001

only thing is youj need the inequalites equations, is all

- anonymous

I'm sorry I am really bad at this .

- nikato

|dw:1437088210344:dw|
now this is where D and E are

- nikato

|dw:1437088327956:dw|
and if you look at the x-coordiate, its somewhere between these two numbers, right?

- anonymous

yes

- nikato

and how would you write this as an inequaulity?

- jdoe0001

notice the primary colors
recall that yellow and red make green
notice where they go about
notice those lines
use those lines, or those points given, to get the equations for the inequalities

##### 1 Attachment

- jdoe0001

notice that if you use those 2 lines
and their shaded "true" regions
they intersect on the "green zone", that comprises D and E

- anonymous

yes so um

- jdoe0001

so... get the equations for those lines first :)

- anonymous

-2+4 < 2+4? I really don't know Im sorry.. Math isn't really my thing ..

- jdoe0001

well... have you covered "slopes" yet?

- anonymous

yes but its pretty recent I haven't "mastered," it..

- jdoe0001

ok well...
let's ... hmmm seee
if we can get the lline equations first
notice, the equations for lines AF and lines BC are what we're after
one sec

- Mertsj

C is the point (2,1) and B is the point (-4,-2) Find the slope of the line joining those two points.

- jdoe0001

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({\color{red}{ -5}}\quad ,&{\color{blue}{ 5}})\quad
% (c,d)
F&({\color{red}{ 3}}\quad ,&{\color{blue}{ -4}})\\
B&({\color{red}{ -4}}\quad ,&{\color{blue}{ -2}})\quad
% (c,d)
C&({\color{red}{ 2}}\quad ,&{\color{blue}{ 1}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\
% point-slope intercept
y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)
anyhow... there
get the slopes of those, and then get their EQUAtions first
so we can get the inequality after

- anonymous

Is there any simpler way of explaining it?

- anonymous

or no? because I could figure it out I would just need time ..

- jdoe0001

hmmm doubt it, that's... kinda straightforward methinks

- anonymous

ah okie Well then I better get to researching .-.

- jdoe0001

k

- anonymous

I give up :') thanks guys for trying .

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