What is the exact value of cos(arcsin(1/4))? Kindly explain to me how. :)

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What is the exact value of cos(arcsin(1/4))? Kindly explain to me how. :)

Mathematics
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first convert 1/4 into decimals ??@mathway
1/4= 0.25
now as we know sin 30 =0.5 so sin 15 = 0.25 now arcsin (0.25) = 15 degress okay ?? @mathway

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Did you get it till now
Nothing comes up in my notifications. Sorry.
oh where you are having difficulty ?
Why did sin 30 become sin 15? Is it because we ant to get the half of it (to get 0.5)?
And I didn't know sin 30 =0.5. Yikes!
it is in table of trigonometry , you should remember the whole table yourself sin 30 degree = 0.5 so sin 15 degree = 0.25 okay ???
Since arcsin1/4 is equals to 15, we now need to get the cos of 15?
I was looking up for the tigro table, but I don't know which one is that. Could you please tell what it looks like? :)
yes you are correct arcsin (1/4) = 15 we need to know what is the value for cos 15 we do same for cos 15 as we do for sin 15 I mean first we take our the value of cos 30 which is cos 30 =0.866 so what will be the value for cos 15 Tell me your self
Is it the half of 0.866?
yes
Also, is this the trigonometry table? https://www.google.com/search?q=table+of+trigonometry&rlz=1C1CHMO_enUS611US611&espv=2&biw=1517&bih=783&source=lnms&tbm=isch&sa=X&ved=0CAYQ_AUoAWoVChMI76LS7e3gxgIVxCoeCh2KSgCX&dpr=0.9#tbm=isch&q=table+of+trigonometry+with+decimals&imgrc=ao8XQOd5IYy6OM%3A
and here is the table https://www.google.com.pk/search?q=trigonometry+table+0-90&biw=1366&bih=659&tbm=isch&imgil=2xbrLGCsrMX9UM%253A%253BridUNDj2YryhWM%253Bhttp%25253A%25252F%25252Fwww.youtube.com%25252Fwatch%25253Fv%2525253DtyS0SPoi5dA&source=iu&pf=m&fir=2xbrLGCsrMX9UM%253A%252CridUNDj2YryhWM%252C_&usg=__QPUH5cIvtTDW1iz3C3WP0uRTSRk%3D&ved=0CCYQyjdqFQoTCLbZz-rw4MYCFQQ_FAodw_cG0w&ei=kUioVfbMNYT-UMPvm5gN#imgrc=tOTEJZ-k-SQXQM%3A&usg=__QPUH5cIvtTDW1iz3C3WP0uRTSRk%3D
So it is 0.433.
yes you are correct Good job smart girl :)
Lol I'm really sorry if I seem dumb to you haha. I'm taking Pre-Calc and never took Trigonometry, so this topic is kinda new to me. But thank you so much for the help @Haseeb96 ! :)
oh well, I am here to sort out the problems of my friends Whenever you need help in math or physics you can tag me If i will be able to solve that , I would have tried my best. @mathway Welcome again :)

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