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-Welp-

  • one year ago

Trig help

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  1. -Welp-
    • one year ago
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    |dw:1437096534099:dw| What are the values of x and y? How I am I supposed to solve this?

  2. anonymous
    • one year ago
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    This is about the properties of a 30-60-90 triangle. In a 30-60-90 triangle, the sides will always be proportionate to each other like this. |dw:1437096781023:dw| The side opposite to 30 degrees is always half of the hypotenuse and the side opposite the 60 degrees is the short side * \(\sqrt{3}\).

  3. -Welp-
    • one year ago
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    x= 42 y= 21?

  4. anonymous
    • one year ago
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    The side opposite 30 degrees is half of the hypotenuse. Is 21 half of \(21\sqrt{3}\)?

  5. -Welp-
    • one year ago
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    y= \[10.5\sqrt{3}?\]

  6. mathstudent55
    • one year ago
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    yes

  7. mathstudent55
    • one year ago
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    y is opposite the 30-deg angle, so y is the short leg which is half the hypotenuse. \(y = 10.5 \sqrt 3\) You are correct above. Then x is the long leg which is \(\sqrt 3\) times the short leg \(x = (10.5 \sqrt 3)(\sqrt 3) \)

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