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SolomonZelman
 one year ago
Random....
SolomonZelman
 one year ago
Random....

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\large\color{black}{ \displaystyle y'+\frac{1}{x}y={\rm W} }\) (W is a constant) Of course, it is a linear equation. Integrating factor: \(\large\color{black}{ \displaystyle e^{{\rm H}(x)}= e^{\ln(x)}=x}\) multiplying times this integrating factor: \(\large\color{black}{ \displaystyle y'x+y={\rm W}x }\) \(\large\color{black}{ \displaystyle y'x+y\Longrightarrow \frac{dy}{dx}\left[yx \right] }\) \(\large\color{black}{ \displaystyle \frac{dy}{dx}\left[yx \right]={\rm W}x }\) \(\large\color{black}{ \displaystyle y=({\rm W}/2)x+C/x }\)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Haha, had me interested, is this suppose to be a differential equation? :P

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2Was like dah... jk It was random.... (wouldn't envoke a series solution here)
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