I medal! :> In order for the data in the table to represent a linear function with a rate of change of –8, what must be the value of m? m = 2 m = 3 m = 19 m = 35

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I medal! :> In order for the data in the table to represent a linear function with a rate of change of –8, what must be the value of m? m = 2 m = 3 m = 19 m = 35

Mathematics
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We have three points: (10,27), (11,m), (12,11) Let's pick two of them, say (10,27) & (11,m)
You plug those coordinates into the slope formula \[\Large Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\] \[\Large Slope = \frac{m-27}{11-10}\] replace "slope" with -8 because this is what we want the slope to be \[\Large -8 = \frac{m-27}{11-10}\] from here you solve for m

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I'll let you do this part. Tell me what you get
m=19 Can you help me with more? @jim_thompson5910
m = 19 is correct
sure I can help
Ellen makes and sells bookmarks. She graphs the number of bookmarks sold compared to the total money earned. What is the rate of change for the function graphed to the left? 2/5 5/4 5/3 5/2
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you'll use the slope formula again you can pick two points, say (4,0) and (8,10)
(x1,y1) = (4,0) x1 = 4 y1 = 0 -------------- (x2,y2) = (8,10) x2 = 8 y2 = 10
okay I'm using it now
@jim_thompson5910 I got -10... bur I think I messed up >.<
what is y2 - y1 equal to?
10
how about x2-x1
2/5 .. is that the answer >.<
you got it flipped
the y difference goes over the x difference
10/4 = 5/2
Ohhh okay thank you
np

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