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anonymous
 one year ago
Please help :)
Describe the roots of the equation shown below.
64x^216x+1=0
A. There are two real, irrational roots.
B. There is one real, double root.
C. There are two real, rational roots.
D. There are two complex roots.
anonymous
 one year ago
Please help :) Describe the roots of the equation shown below. 64x^216x+1=0 A. There are two real, irrational roots. B. There is one real, double root. C. There are two real, rational roots. D. There are two complex roots.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a y idea what it might be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use quadratic equation to solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I know how to solve it but just not sure which one haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0both real and rational unless imaginary numbers were put into equation (Im assuming not so considering it wasnt mentioned in the question itself), and also one has negative coefficient, theres no need to even consider it. No need to solve

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[64x^216x+1=(8x1)(8x1)=0\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[x=\frac{1}{8}orx =\frac{1}{8}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm so confused so it's not two real rational like what Reealcheyenne said?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1There is one root which occurs twice. That is what we call a double root. It corresponds to a point of tangency of the graph to the x axis at that number.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh! alright thanks so much :)
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