## anonymous one year ago Please help :) Describe the roots of the equation shown below. 64x^2-16x+1=0 A. There are two real, irrational roots. B. There is one real, double root. C. There are two real, rational roots. D. There are two complex roots.

1. anonymous

Do you have a y idea what it might be?

2. anonymous

c

3. anonymous

WHy?

4. anonymous

have you solved?

5. anonymous

You can use quadratic equation to solve

6. anonymous

Yeah I know how to solve it but just not sure which one haha

7. Mertsj

Factor it.

8. anonymous

both real and rational unless imaginary numbers were put into equation (Im assuming not so considering it wasnt mentioned in the question itself), and also one has negative coefficient, theres no need to even consider it. No need to solve

9. Mertsj

$64x^2-16x+1=(8x-1)(8x-1)=0$

10. Mertsj

$8x-1=0 or 8x-1=0$

11. anonymous

so 1/8

12. Mertsj

$x=\frac{1}{8}orx =\frac{1}{8}$

13. Mertsj

1 Double Root

14. anonymous

I'm so confused so it's not two real rational like what Reealcheyenne said?

15. Mertsj

no

16. Mertsj

There is one root which occurs twice. That is what we call a double root. It corresponds to a point of tangency of the graph to the x axis at that number.

17. anonymous

ohhh! alright thanks so much :)

18. Mertsj

yw