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if you are on please respond i think i got ur answer
okay thank you
to find the minimum value of the first one convert to vertex form
well first in the simpliset way do u want anwser of show the answer
for the second one part of the graph will lok like:- |dw:1437137302887:dw|
go the graph and if you got the calculator a ti84+ to be exact there will be a graph button and thats how you graph like he has above for the second part but also for the first part ill send a picture for you to understand
you can find the minimum value of the first one by completing the square to get the vertex form
|dw:1437137623006:dw| kinda messed up i know
okay so would he answer be B?
f(x) = 4x2 + 8x + 1 f(x) = 4(x^2 + 2x) + 1 = 4(x + 1)^2 -4 = 1 = 4(x + 1)^2 - 3 that's vertex form for a(x - b)^2 + c vertex is (b , c) so comparing with our result we see that at the vertex which is a minimum the coordinates are (-1,-3)
ooo I see so the answer is a?
from the drawing you can see that the minimum is at (-1,0) for function 2 so what is the correct option?
No it s A
because its Function 1 has the least minimum value and its coordinates are (0, 1). i kmow my graph is slopy but im pretty sure its B
Function 1 has the least minimum value thats for sure - - I'll recheck by graphing it on my calculator
okay thank you
Yes the minimum for Function 1 is at (-1,-3) so that makes it less than the minimum for Function 2.
which would make the answer a