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mathmath333
 one year ago
quadratic equation
mathmath333
 one year ago
quadratic equation

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MrNood
 one year ago
Best ResponseYou've already chosen the best response.1did you miss an x out of the second term?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0are you sure there isn't a "x" missing in the middle term ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} &\normalsize \text{If the roots of the equation }\hspace{.33em}\\~\\ &a(bc)x^2+b(ca)x+c(ab)=0 \hspace{.33em}\\~\\ &\normalsize \text{are equal , then }\ a,b,c \ \text{are in} \hspace{.33em}\\~\\ &a.)\ AP \hspace{.33em}\\~\\ &b.)\ GP \hspace{.33em}\\~\\ &c.)\ HP \hspace{.33em}\\~\\ &d.)\ \normalsize \text{cannot be determined} \hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0you may simply set the discriminant equal to 0 and try to get a relation between a,b,c

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1but the discriminant contains a,b & c and is only one equation not sure you can derive much from that b^2 = 4ac (but NOTE this refers to the standard quadratic form  NOT the abc in your equation))

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i tried that and got \(\large \color{black}{\begin{align} b^2(a^2+c^2)2abc(a+c2b)=0 \hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1answer given is \( c.)\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1so i have to show \(\large \color{black}{\begin{align} &b^2(a^2+c^2)2abc(a+c2b)=0\hspace{.33em}\\~\\ &\Longleftrightarrow\hspace{.33em}\\~\\ &\dfrac{2}{b}=\dfrac{1}{a}+\dfrac{1}{c} \hspace{.33em}\\~\\ \end{align}}\)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1hint : if a+b+c=0 in standard \[ax^2+bx+c=0 \\x_1=1 ,x_2=\frac{c}{a}\] in your case sum of coefficient is =0 a(b−c)+b(c−a)+c(a−b)=abac +bc ab +ac bc =0 can you go on ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i am confused , how u got \(x_1=1\) and \(x_2=\dfrac{c}{a}\) if \(a+b+c=0\)

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1I would also dispute that a+b+c=0 implies that ax^2 + bx +c =0
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