The planet Jupiter rotates every 9.9 hours and has a diameter of 88,846 miles. If you’re standing on its equator, how fast are you travelling?

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The planet Jupiter rotates every 9.9 hours and has a diameter of 88,846 miles. If you’re standing on its equator, how fast are you travelling?

Trigonometry
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relative to what?
work out the ANGULAR velocity in rad/s (omega) the linear velocity of the equator is r times omega be careful of the units miles/sec miles per hour.....
So Ill be using Linear Speed or Angular Speed formula?
\(Ref:\) http://www.wiley.com/college/sc/trigonometry/resources/annotated_instructors_edition/Young_Trig_3e_AIE_c03RadianMeasureandtheUnitCircleApproach.pdf Might help you as I forgot the tricks behind it to solve easily.
Will check it... thanks koi
I believe the formula is distance / time = speed. So if the distance is 88,848 miles, and the time is 9.9 hours...
Sorry. *88,846
What formula will be used? Need help plssss :(
If you divide the distance by time, then you get the speed
@KyanTheDoodle that is not correct the distance travelled by the equator is I rev in 9.9 hours I rev = 2 pi radians
work out the ANGULAR velocity in rad/s (omega) the linear velocity of the equator is r times omega
Doesn't necessarily mean I'm not correct. As 100 miles divided by 1 hour is still 100 miles an hour, but 100 miles divided by 2 hours is 50 miles an hour.
But I DO see that it's the diameter
@KyanTheDoodle you have quoted the distance travelled as the diameter - that is NOT the distance travelled - so you are incorrect
Yes, I literally just said that I was wrong on that part. But the rest is right. I just misread the situation.
another way to look at it is distance travelled = circumference of eqator (you know the radius so this is easy to work out) velocity is then circumference /time to rotate 1 circumference
Meaning, Ill get the circumference by 2(pi)radius, then divide it by the time (9.9 hours) what unit is the answer?
You could do that, or just once with the diameter given.

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