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tmagloire1

  • one year ago

Where is (x+2)/((x^2-2x-8) discontinuous

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  1. anonymous
    • one year ago
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    Oh. Where a line is discontinuous is basically where a point on the graph of the function cannot exist. This is indicated by a open circle on the graph. |dw:1437150289650:dw|

  2. anonymous
    • one year ago
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    So to first do this, factor the denominator of \[(x+2)/((x^2-2x-8) \]

  3. tmagloire1
    • one year ago
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    (x+2)(x-4)

  4. anonymous
    • one year ago
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    Yes! Just another side note, is there by chance answer choices?

  5. tmagloire1
    • one year ago
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    –2 –2, 4 4 f(x) is continuous everywhere

  6. anonymous
    • one year ago
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    So the function cannot exist if the denominator equals 0. So this means...?

  7. tmagloire1
    • one year ago
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    It has a discontinuity?

  8. anonymous
    • one year ago
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    Basically you have to find the "zeroes" of the denominator, So x - 4 = 0, and x+2 = 0

  9. anonymous
    • one year ago
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    SO if you solve for x, what would they be?

  10. anonymous
    • one year ago
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    Hello?

  11. tmagloire1
    • one year ago
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    Sorry internet trouble

  12. tmagloire1
    • one year ago
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    So it would be 4 and -2

  13. tmagloire1
    • one year ago
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    @whatdoesthismean

  14. anonymous
    • one year ago
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    yes. thats correct. sorry i was helping another person

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