tmagloire1
  • tmagloire1
Where is (x+2)/((x^2-2x-8) discontinuous
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Oh. Where a line is discontinuous is basically where a point on the graph of the function cannot exist. This is indicated by a open circle on the graph. |dw:1437150289650:dw|
anonymous
  • anonymous
So to first do this, factor the denominator of \[(x+2)/((x^2-2x-8) \]
tmagloire1
  • tmagloire1
(x+2)(x-4)

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anonymous
  • anonymous
Yes! Just another side note, is there by chance answer choices?
tmagloire1
  • tmagloire1
–2 –2, 4 4 f(x) is continuous everywhere
anonymous
  • anonymous
So the function cannot exist if the denominator equals 0. So this means...?
tmagloire1
  • tmagloire1
It has a discontinuity?
anonymous
  • anonymous
Basically you have to find the "zeroes" of the denominator, So x - 4 = 0, and x+2 = 0
anonymous
  • anonymous
SO if you solve for x, what would they be?
anonymous
  • anonymous
Hello?
tmagloire1
  • tmagloire1
Sorry internet trouble
tmagloire1
  • tmagloire1
So it would be 4 and -2
tmagloire1
  • tmagloire1
@whatdoesthismean
anonymous
  • anonymous
yes. thats correct. sorry i was helping another person

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