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anonymous
 one year ago
What is the simplified form of x minus 5 over x squared minus 3x minus 10 ⋅ x plus 2 over x squared plus x minus 12?
anonymous
 one year ago
What is the simplified form of x minus 5 over x squared minus 3x minus 10 ⋅ x plus 2 over x squared plus x minus 12?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437150497955:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 1/(x+3)(x2) as an answer

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1is your expression like this: \[\frac{{x  5}}{{{x^2}  3x  10}}:\frac{{x + 2}}{{{x^2} + x  12}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x5/(x5)(x+2) timex x+2/(x+4)(x3)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have these steps:

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\begin{gathered} \frac{{x  5}}{{{x^2}  3x  10}} \cdot \frac{{x + 2}}{{{x^2} + x  12}} = \hfill \\ \hfill \\ = \frac{{x  5}}{{\left( {x  5} \right)\left( {x + 2} \right)}} \cdot \frac{{x + 2}}{{\left( {x  3} \right)\left( {x + 4} \right)}} = ...? \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what's going on? @Michele_Laino

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1after a simplification I got this: \[\frac{1}{{\left( {x  3} \right)\left( {x + 4} \right)}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks :) Can I ask another?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the simplified form of the quantity x over 4 plus y over 3 all over the quantity x over 3 minus y over 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437151350249:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1do you mean this: \[\frac{{\frac{x}{4} + \frac{y}{3}}}{{\frac{x}{4}  \frac{y}{3}}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \frac{{\frac{x}{4} + \frac{y}{3}}}{{\frac{x}{4}  \frac{y}{3}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no the bottom one is x/3  y/4

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! we have to compute the least common multiple at numerator and at denominator, of your main fraction, which is 12, so we get: \[\Large \frac{{\frac{x}{4} + \frac{y}{3}}}{{\frac{x}{3}  \frac{y}{4}}} = \frac{{\frac{{3x + 4y}}{{12}}}}{{\frac{{4x  3y}}{{12}}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we can get rid of the denominator of 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the oblique asymptote of the function f(x) = the quantity x squared minus 5x plus 6 over the quantity x minus 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got x1 as the oblique asymptote

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1your function is like this: \[\frac{{\sqrt {{x^2}  5x + 6} }}{{x  4}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No. It is without the radical sign

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, sorry, is like this? \[\frac{{{x^2}  5x + 6}}{{x  4}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1If I write the asymptote like this: y=mx+q then we have: \[\Large \begin{gathered} m = \mathop {\lim }\limits_{x \to \infty } \frac{{f\left( x \right)}}{x} = \mathop {\lim }\limits_{x \to \infty } \frac{{{x^2}  5x + 6}}{{x\left( {x  4} \right)}} = \hfill \\ \hfill \\ = \mathop {\lim }\limits_{x \to \infty } \frac{{{x^2}\left( {1  \frac{5}{x} + \frac{6}{{{x^2}}}} \right)}}{{{x^2}\left( {1  \frac{4}{{{x^2}}}} \right)}} = \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay:) Kinda confused but I'm getting it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can't you just use synthetic divison?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that limit is 1, so your slope is right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to go but I need more help. When will you be back?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I stay here for at least 2 hours

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok:) Thank you. U gtg now!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1wait I have to compute the quantity q

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops..please wait...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have this formula: \[\large \begin{gathered} q = \mathop {\lim }\limits_{x \to \infty } \left\{ {f\left( x \right)  mx} \right\} = \mathop {\lim }\limits_{x \to \infty } \left\{ {f\left( x \right)  x} \right\} = \hfill \\ \hfill \\ = \mathop {\lim }\limits_{x \to \infty } \left\{ {\frac{{{x^2}  5x + 6}}{{x  4}}  x} \right\} = \mathop {\lim }\limits_{x \to \infty } \left\{ {\frac{{{x^2}  5x + 6  {x^2} + 4x}}{{x  4}}} \right\} = \hfill \\ \hfill \\ = \mathop {\lim }\limits_{x \to \infty } \left\{ {\frac{{6  x}}{{x  4}}} \right\} = \mathop {\lim }\limits_{x \to \infty } \left\{ {  1 + \frac{2}{{x  4}}} \right\} = ...? \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that limit is 1, so I confirm your answer, namely the equation of your asymptote is: y=x1
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