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anonymous

  • one year ago

Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following equations shows the path of the softball? H(t) = −16t2 + 26 H(t) = −16t2 + 26t H(t) = −16t2 + 8t + 18 H(t) = −16t2 + 18t + 8

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  1. welshfella
    • one year ago
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    note at time = 0 h = 8

  2. anonymous
    • one year ago
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    The starting height is the height at time zero. So you need to choose a function with H(0) = 8. And the velocity is the derivative of position, so you need the function with H'(0) = 18. What do you think?

  3. anonymous
    • one year ago
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    i think the answer is A

  4. anonymous
    • one year ago
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    If you put t=0 into A, do you get H(0) = 8 ?

  5. welshfella
    • one year ago
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    you get 26 if you put t = 0 into A

  6. anonymous
    • one year ago
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    just kidding its C

  7. anonymous
    • one year ago
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    Right on. Well done!

  8. anonymous
    • one year ago
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    thank you!

  9. welshfella
    • one year ago
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    put t = 0 into C and what do you get?

  10. anonymous
    • one year ago
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    You're welcome.

  11. welshfella
    • one year ago
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    ?????

  12. welshfella
    • one year ago
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    Its D

  13. welshfella
    • one year ago
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    h is 8 when t = 0 h(0) = -16(0)^2 + 18(0) = 8 = 8

  14. anonymous
    • one year ago
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    plug O in for T and you get C

  15. anonymous
    • one year ago
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    were not trying to get 8 were trying to get 18

  16. welshfella
    • one year ago
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    plug 0 for t in C and you get h = 18 - but its not 18 at time 0 its 8

  17. welshfella
    • one year ago
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    believe me the answer is D

  18. welshfella
    • one year ago
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    Omar is not 18 feet tall!! lol

  19. anonymous
    • one year ago
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    were trying to find the path of the softball

  20. welshfella
    • one year ago
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    I know that but if you want to accept the wrong answer its up to you

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