Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following equations shows the path of the softball? H(t) = −16t2 + 26 H(t) = −16t2 + 26t H(t) = −16t2 + 8t + 18 H(t) = −16t2 + 18t + 8

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Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following equations shows the path of the softball? H(t) = −16t2 + 26 H(t) = −16t2 + 26t H(t) = −16t2 + 8t + 18 H(t) = −16t2 + 18t + 8

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note at time = 0 h = 8
The starting height is the height at time zero. So you need to choose a function with H(0) = 8. And the velocity is the derivative of position, so you need the function with H'(0) = 18. What do you think?
i think the answer is A

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Other answers:

If you put t=0 into A, do you get H(0) = 8 ?
you get 26 if you put t = 0 into A
just kidding its C
Right on. Well done!
thank you!
put t = 0 into C and what do you get?
You're welcome.
?????
Its D
h is 8 when t = 0 h(0) = -16(0)^2 + 18(0) = 8 = 8
plug O in for T and you get C
were not trying to get 8 were trying to get 18
plug 0 for t in C and you get h = 18 - but its not 18 at time 0 its 8
believe me the answer is D
Omar is not 18 feet tall!! lol
were trying to find the path of the softball
I know that but if you want to accept the wrong answer its up to you

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