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anonymous
 one year ago
y = 5
y = 3x  4
PLEASE HELP ME WITH 3 QUESTIONS THAT'S ALL JUST 3!!
anonymous
 one year ago
y = 5 y = 3x  4 PLEASE HELP ME WITH 3 QUESTIONS THAT'S ALL JUST 3!!

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3here we can write this: \[\Large 3x  4 = 5\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3now I add 4 to both sides: \[\Large 3x  4 + 4 = 5 + 4\] please continue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is 3,9 right or is it wrong what is it , I'm really frustrated so ....

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3after a simplification, we can write: \[\Large 3x = 9\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3now, please divide by 3, both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what sides am I dividing it by

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: dw:1437154156003:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to write it as an ordered pair

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3ok! we have: x=3 and y=5, so we can write: (3,5)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the solution(s) to the system, if one or more exist. Write your answer as an ordered pair. Round to the nearest hundredth, if necessary. \begin{array}{l}y = {x^2} + 4x  3\\x = 1\end{array} this is the other one, I have one more I need help on

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have to substitute x=1 into the first equation, so we can write: \[y = {1^2} + 4 \times 1  3 = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3please continue, what is y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that;s what I got for y

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: \[y = {1^2} + 4 \times 1  3 = 1 + 4  3 = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have: y=2 and x=1 so we can write: (1,2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Explain how to find the solution(s) to the system. Give the solutions(s) as ordered pairs rounded to the nearest hundredth, if necessary. \begin{array}{l}y =  0.5{x^2} + x + 6\\y = 3.25\end{array} this is the last question I need help on I need help finding the ordered pairs

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have to apply the transitive property, so we can write: \[\Large  0.5{x^2} + x + 6 = 3.25\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3it is a quadratic equation, since we can rewrite it as follows: \[\Large 0.5{x^2}  x  2.75 = 0\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3or using fraction instead decimal numbers, we get: \[\Large \frac{{{x^2}}}{2}  x  \frac{{11}}{4} = 0\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3now, I multiply both sides by 4, so I can write: \[\Large \begin{gathered} 4 \times \left( {\frac{{{x^2}}}{2}  x  \frac{{11}}{4}} \right) = 0 \times 4 \hfill \\ 4 \times \frac{{{x^2}}}{2} + 4 \times \left( {  x} \right) + 4 \times \left( {  \frac{{11}}{4}} \right) = 0 \hfill \\ 2{x^2}  4x  11 = 0 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3note that equation is an equation like this: \[\Large a{x^2} + bx + c = 0\] where: \[\Large \begin{gathered} a = 2 \hfill \\ b =  4 \hfill \\ c =  11 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3so we can apply the standard formula: \[\Large x = \frac{{  b \pm \sqrt {{b^2}  4 \times a \times c} }}{{2 \times a}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3in order to find the values of x

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3after a simple substitution, we get: \[\large \begin{gathered} x = \frac{{  b \pm \sqrt {{b^2}  4 \times a \times c} }}{{2 \times a}} = \frac{{4 \pm \sqrt {{{\left( {  4} \right)}^2}  4 \times 2 \times \left( {  11} \right)} }}{{2 \times 2}} = \hfill \\ \hfill \\ = \frac{{4 \pm \sqrt {16 + 88} }}{4} \hfill \\ \end{gathered} \] please continue

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: we have 2 values for x: \[\Large \begin{gathered} {x_1} = \frac{{4 + \sqrt {16 + 88} }}{4} = ...? \hfill \\ \hfill \\ {x_2} = \frac{{4  \sqrt {16 + 88} }}{4} = ...? \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: \[\begin{gathered} {x_1} = \frac{{4 + \sqrt {16 + 88} }}{4} = \frac{{4 + \sqrt {104} }}{4} = \frac{{4 + 10.2}}{4} = \frac{{14.2}}{4} = ...? \hfill \\ \hfill \\ {x_2} = \frac{{4  \sqrt {16 + 88} }}{4} = \frac{{4  \sqrt {104} }}{4} = \frac{{4  10.2}}{4} = \frac{{  6.2}}{4} = ...? \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3you have to divide by 4, namely 14.20/4=...? 6.20/4=...?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have: x1= 3.55 x2=1.55

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3so the requested pairs, are: (3.55, 3.25) (1.55, 3.25)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need two that I wanted you to check

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the solution(s) to the system, if one or more exist. Write your answer as an ordered pair. \begin{array}{l}y = 3{x^2} + 2x + 4\\x = 4\end{array} I have 156,4 as my answer

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3substituting x=4 into the first equatiuon, we get: \[y = 3 \times {4^2} + 2 \times 4 + 4 = 3 \times 16 + 8 + 4 = 48 + 12 = 60\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3so the requested pair is: (4, 60)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one of the answer they have is (4,60) and (60 ,4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one with 3,5 wasn't right

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3please what question do you refer to?
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