anonymous
  • anonymous
Find all polar coordinates of point P where P = (5, -pi/6) (5, -pi/6 + 2nπ) or (-5, -pi/6 + 2nπ) (5, -pi/6 + 2nπ) or (-5, -pi/6 + (2n + 1)π) (5, -pi/6 + 2nπ) or (5, pi/6 + (2n + 1)π) (5, -pi/6 + (2n + 1)π) or (-5, -pi/6+ 2nπ)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@welshfella @Astrophysics
amoodarya
  • amoodarya
|dw:1437154842292:dw| hint : \[-\frac{\pi}{6}=-\frac{\pi}{6}+2kpi\]
anonymous
  • anonymous
i got C is that right?

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anonymous
  • anonymous
@amoodarya
welshfella
  • welshfella
not sure about this one
amoodarya
  • amoodarya
pi/6+(2n+1)pi is not equal by -pi/6+2kpi
amoodarya
  • amoodarya
(5, -pi/6 + 2nπ) is ok
anonymous
  • anonymous
so its not C
anonymous
  • anonymous
@amoodarya
anonymous
  • anonymous
yes its not C
anonymous
  • anonymous
b?
anonymous
  • anonymous
help!!
anonymous
  • anonymous
@amoodarya
anonymous
  • anonymous
its A..i think
anonymous
  • anonymous
\[here\ P=(r,\theta)=(5,-\frac{ \pi }{ 6}). since\ (r,\theta+2n \pi) \ same \ polar\ point\ as\ (r, \theta).\\ \therefore\ (5, -\frac{ \pi }{ 6}+2n \pi) is\ same\ as\ (5,-\frac{ \pi }{ 6})\\As \ we\ can\ take\ r\ as \ negative\ i.e.\ -r,\ provided\ that (-r,\theta) \ is\ plotted\ \\similarly\ (r, \theta \pm \pi).\ so \ again\ \it\ can \ be \ written\ as\ (-5,-\frac{ \pi }{ 6}),\ giving\\ general\ point\ as\ (-5,-\frac{ \pi }{ 6}+2n \pi).\\so\ general \ point\ can\ be \ written\ as\ (5,-\frac{ \pi }{ 6} +2n \pi)\ or (-5,-\frac{ \pi }{ 6} +2n \pi).\\ clearly\ option\ first\ is\ correct.\]

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