## anonymous one year ago For the function f(x) = –2(x + 3)2 − 1, identify the vertex, domain, and range.

1. amoodarya

$f(x) = –2(x + 3)^2 − 1$ domain ; no denominator ,no radical ---->$D_f=R$ range: $f(x) = –2(x + 3)^2 − 1\\y=–2(x + 3)^2 − 1\\y+1=-2(x+3)^2\\(x+3)^2=\frac{y+1}{-2}\\(x+3)^2 \geq 0 \rightarrow \frac{y+1}{-2} \geq 0\\ \rightarrow y+1 \leq 0 \rightarrow y \leq -1$ for vertex $y=a(x+b)^2 +c \rightarrow x_{vertex}=-b$

2. anonymous

so would the vertex be (-3, -1) or (3, -1) ?

3. anonymous

-3 right?

4. anonymous

okay yeah i got it right thank you!