anonymous
  • anonymous
Find the product 7n^4 * 2n^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Nnesha
  • Nnesha
when you mulitplyc same bases you should add their exponents exxample \[\huge\rm x^m \times x^n = x^{m+n}\]
anonymous
  • anonymous
i mean 14^9
Nnesha
  • Nnesha
9? to the 9 power ? multiply coefficient (7 times 2)(n^4 times x^5)

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Nnesha
  • Nnesha
14 is not to the 9 power the variable is to the 9 poawer
anonymous
  • anonymous
i am still so confused
anonymous
  • anonymous
so like 14^20
Nnesha
  • Nnesha
nope 9 is right bec you have to add exponents so n^9 not 14^9
anonymous
  • anonymous
okay so it would be 14n^9
Nnesha
  • Nnesha
\[\huge\rm (7 \times 2)(n^4 \times n^5)=(7 \times 2) n^{4+5}\]
Nnesha
  • Nnesha
yes that's right
anonymous
  • anonymous
5xy^5 * -3x^4y^3 how would that one be set up to find the product
Nnesha
  • Nnesha
* <--is that a multiplicationz sign ?
anonymous
  • anonymous
yea
Nnesha
  • Nnesha
that's same like we just did multiply coefficients and add exponents of variables
Nnesha
  • Nnesha
x is same as x to the one power x=x^1
anonymous
  • anonymous
so it would be like -15^xy13? or -15x^5y8
anonymous
  • anonymous
-15x^5y^8 i wrote that wrong
Nnesha
  • Nnesha
add coefficient of same variables you can't add 3 exponent of y with 5 exponent of x x^{1+4}
Nnesha
  • Nnesha
so which one is correct ?
anonymous
  • anonymous
so it would be -15x^5y^8
anonymous
  • anonymous
thank you it was right
Nnesha
  • Nnesha
np :=)

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