anonymous
  • anonymous
Find the horizontal asymptote of f(x)= x^2+3x-2/x-2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I appreciate any help
anonymous
  • anonymous
You sure that is 3x - 2 in numerator and not 3x + 2 ??
anonymous
  • anonymous
Yes it's in the numerator

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More answers

anonymous
  • anonymous
As you can see, degree of numerator is greater than degree of denominator, you will get Slant Asymptote...
anonymous
  • anonymous
Ok
anonymous
  • anonymous
Do you know the Long Division Method??
anonymous
  • anonymous
No :(
anonymous
  • anonymous
You have to just divide numerator by denominator.. As you do simple division and then find out the quotient..
anonymous
  • anonymous
Ok so divide x^2+3x-2 by x-2?
anonymous
  • anonymous
yep...
anonymous
  • anonymous
Would it be the same as using synthetic division?
anonymous
  • anonymous
|dw:1437159263381:dw|
anonymous
  • anonymous
yes, you can do synthetic division too..!!!
anonymous
  • anonymous
So, \(y = x + 5\), this is the Slant Asymptote in this case..
anonymous
  • anonymous
Where degree of numerator is greater than degree of denominator, there is no horizontal asymptote but there is slant asympote, as you can find that by \(y = quotient\), for that just use Long Division and find the quotient..
anonymous
  • anonymous
So I got x+1 - (4/x+2) :/
anonymous
  • anonymous
Wait so the answer is none?
anonymous
  • anonymous
yes None is the answer for this.. :P
anonymous
  • anonymous
There is no horizontal asymptote? What a trick question 😅
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
I just told how to find slant asymptote equation if you do not have Horizontal asymptote..
anonymous
  • anonymous
Oh on :) thanks
anonymous
  • anonymous
Ok :D
anonymous
  • anonymous
Thanks again bye~
anonymous
  • anonymous
See, horizontal asymptote means you will get line parallel to x-axis or where y = 0, but if asymptote is not horizontal, then it must be inclined and y \(\ne\) 0 there, so how to find y there, I just told you that.. :)
anonymous
  • anonymous
\(\dagger\) ..

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