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anonymous
 one year ago
Find the horizontal asymptote of f(x)= x^2+3x2/x2
anonymous
 one year ago
Find the horizontal asymptote of f(x)= x^2+3x2/x2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I appreciate any help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You sure that is 3x  2 in numerator and not 3x + 2 ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes it's in the numerator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As you can see, degree of numerator is greater than degree of denominator, you will get Slant Asymptote...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know the Long Division Method??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have to just divide numerator by denominator.. As you do simple division and then find out the quotient..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so divide x^2+3x2 by x2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would it be the same as using synthetic division?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437159263381:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, you can do synthetic division too..!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, \(y = x + 5\), this is the Slant Asymptote in this case..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where degree of numerator is greater than degree of denominator, there is no horizontal asymptote but there is slant asympote, as you can find that by \(y = quotient\), for that just use Long Division and find the quotient..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I got x+1  (4/x+2) :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait so the answer is none?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes None is the answer for this.. :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There is no horizontal asymptote? What a trick question 😅

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just told how to find slant asymptote equation if you do not have Horizontal asymptote..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0See, horizontal asymptote means you will get line parallel to xaxis or where y = 0, but if asymptote is not horizontal, then it must be inclined and y \(\ne\) 0 there, so how to find y there, I just told you that.. :)
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